你好,这是我目前的代码:
$sqlpack = "Select * from package_in_plan where plan_id='$package_id' order by plan_id";
$planres = mysqli_query($conn,$sqlpack);
$plan = array();
while ($row1 = mysqli_fetch_assoc($planres)){
$plan[] = $row1['package_id'];
}
$plan_1 = implode(',', $plan);
for ($x = 0; $x < count($plan); $x++) {
$sql_service = "Select * from service_in_package where package_id='".$plan[$x]."'";
$chid = mysqli_query($conn,$sql_service);
while ($row = mysqli_fetch_array($chid)){
$ch_id = $row['service_id'];
$sql = "Select * from itv where status='1' and id='$ch_id' order by number asc";
$results = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($results)){
$nr = $row['id'];
$namn = $row['name'];
$chnr = $row['number'];
echo $nr;
echo $namn;
echo $chnr;
}
}
}
我需要的是按数字排序的输出($ chnr),现在我的代码没有排序,因为它从前一个select($ ch_id)接收特定的id。 我如何让$ results的输出进行排序&#34;按数字排序&#34;。 itv表中的数字是INT。
答案 0 :(得分:0)
您可以使用子查询,这会产生可以排序的单个查询。
$sql = "Select * from itv where status='1' and id IN
(Select service_id from service_in_package where package_id IN
(Select package_id from package_in_plan where plan_id='$package_id' order by plan_id))
order by number asc";
$results = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($results)){
$nr = $row['id'];
$namn = $row['name'];
$chnr = $row['number'];
echo $nr;
echo $namn;
echo $chnr;
}