Javascript倒计时器与php连接到mysql

时间:2016-08-01 03:17:59

标签: javascript php mysql

我正在尝试将倒数计时器达到0时将我的数据库属性从0更新为1.

这是我的代码:

<script language="JavaScript">
var timeleft;
var nextdue;
var tick = 1000;
function parseTime(t) {
    var tt = ("0:00:" + t);
    tt = tt.split(":").reverse();
    return (tt[0] * 1000) + (tt[1] * 60000) + (tt[2] * 3600000);
}
function zeroPad(n) {
    if (n < 10) return "0" + n;
    return "" + n;
}
function makeTime(t) {
    if (t < 0) return "0:00:00";
    var tt = t + 999;
    return Math.floor(tt / 3600000) + ":" +
            zeroPad(Math.floor(tt / 60000) % 60) + ":" +
            zeroPad(Math.floor(tt / 1000) % 60);
}

function startTimer() {
    nextdue = new Date().getTime();
    timeleft = parseTime(document.timerform.timerbox.value);
    console.log(timeleft);
    timeleft = document.getElementById("TL");
    runTimer();
}

function runTimer() {
    document.timerform.timerbox.value = makeTime(timeleft);
    if (timeleft <= 0)window.location.href="closedDBphp.php";
    else {
        var timecorr = (new Date().getTime()) - nextdue;
        if (timecorr > 0 && timecorr < 3000) {
            timeleft -= (tick + timecorr);
            nextdue += tick;
            if (timeleft < 1) setTimeout("runTimer()", tick + timeleft);
            else setTimeout("runTimer()", Math.max(1, tick - timecorr));
        }
        else {
            nextdue = (new Date().getTime()) + tick;
            timeleft -= tick;
            if (timeleft < 1) setTimeout("runTimer()", tick + timeleft);
            else setTimeout("runTimer()", tick);
        }
    }
}

这就是我在.jsp文件中显示倒计时器的方法:

 <div><span id = "TL"></span></div>

这是PHP代码:

<?php
$servername = "localhost";
$username ="root";
$password ="root";
$dbname = "cyber";


//// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
    }

$sql = "UPDATE pin SET closed= 1 ";

    if ($conn->query($sql) === TRUE) {
    echo "Record updated successfully";
     } else {
    echo "Error updating record: " . $conn->error;
    }

    $conn->close();
    ?>

我很想知道我的代码出了什么问题,我也在使用Intellij的想法。请帮我提供建议, 我提前谢谢你们。

0 个答案:

没有答案