如何设置IF语句与数组内的值进行比较？ （红宝石）

Question

是否可以设置条件语句（IF语句）将变量与迭代数组内部值的变量进行比较？我正在寻找类似的东西：

array_of_small_words = ["and","or","be","the","of","to","in"]
if word == array_of_small_words.each 
   # do thing
else
   # do another thing
end

基本上，我想把每个单词弄清楚，但不想为＃34;小单词＆＃34;做这些。我知道我可以做相反的事情并首先迭代数组，然后将每个迭代与单词进行比较，但我希望有更有效的方法。

sentence = ["this","is","a","sample","of","a","title"]
array_of_small_words = ["and","or","be","the","of","to","in"]
sentence.each do |word|
    array_of_small_words.each do |small_words|
       if word == small_words
          # don't capitalize word
       else
          # capitalize word
       end
    end
end

我不确定这是否可行，或者是否有更好的方法可以做到这一点？

谢谢！

Answer 1

sentence = ["this","is","a","sample","of","a","title"]
array_of_small_words = ["and","or","be","the","of","to","in"]

sentence.map do |word|
  array_of_small_words.include?(word) ? word : word.upcase
end
#⇒ ["THIS", "IS", "A", "SAMPLE", "of", "A", "TITLE"]

Answer 2

您要找的是if array_of_small_words.include?(word)。

Answer 3

如果打包在方法和使用频率中，这应该比@ mudasobwa重复使用include?更快。然而，如果我在评论中提到的话，如果mudsie使用了一组查找（一个小的改变，他很清楚），那么不会更快。如果效率很重要，我会更喜欢使用set mod的mudsie方式来回答我的问题。在某种程度上，我只是在下面玩。

我认为他的小词是 ^{_{和，或者，是，in，in，in，in}} 和 ^_尽管

SMALL_WORDS = %w| and or be the of to in notwithstanding |
  #=> ["and", "or", "be", "the", "of", "to", "in", "notwithstanding"] 
(SMALL_WORDS_HASH = SMALL_WORDS.map { |w| [w.upcase, w] }.to_h).
  default_proc = proc { |h,k| h[k]=k }

测试：

SMALL_WORDS_HASH
  #=> {"AND"=>"and", "OR"=>"or", "BE"=>"be", "THE"=>"the", "OF"=>"of",
  #    "TO"=>"to", "IN"=>"in", "NOTWITHSTANDING"=>"notwithstanding"} 
SMALL_WORDS_HASH["TO"]
  #=> "of" 
SMALL_WORDS_HASH["HIPPO"]
  #=> "HIPPO" 

def convert(arr)
  arr.join(' ').upcase.gsub(/\w+/, SMALL_WORDS_HASH)
end

convert ["this","is","a","sample","of","a","title"]
  #=> "THIS IS A SAMPLE of A TITLE"