我在SQL Server 2008 R2中创建了一个存储过程。它执行数据透视表。因此,我需要的下一步是3个新列,它们将在此声明的查询变量中创建。在这3列中,我必须进行计算。
首先,我的存储过程代码: 更新存储过程:
BEGIN
SET NOCOUNT ON;
DECLARE @colNo nvarchar(max)
DECLARE @colSum nvarchar(max)
DECLARE @query nvarchar(max)
SET NOCOUNT ON;
WITH vals AS (
SELECT DISTINCT ds.No
FROM QRTestView ds
)
SELECT @colNo = COALESCE(@colNo + ', ', '') + QUOTENAME(No)
@colSum = COALESCE(@colSum + '+ ', '') + QUOTENAME(No)
FROM vals
ORDER BY No
SET @query = 'SELECT *, [Bonus] + 125 as [Fee],
([Bonus] + 125) * [ALL] as [Fee2]
FROM (
SELECT *,
CASE WHEN 70-(100 - Quote) * 10 > -80 THEN 70-(100 - Quote) * 10 ELSE -70 END as [Bonus]
FROM (
SELECT *, '+@colSum+' as [ALL]
FROM (
SELECT
CAST(ISIN as CHAR(12)) As No,
CAST(Quote as CHAR(7)) As Quote,
CAST(Quote as CHAR(7)) As Q
FROM QRTestView
WHERE Datum >= @from_val and Datum <= @to_val
) AS sel
PIVOT (
COUNT(Q)
FOR No IN ('+ @colNo +')
) AS p
UNION ALL
SELECT ''ALL'', *, '+@colSum+'[ALL]
FROM (
SELECT
CAST(No as CHAR(12)) As No,
COUNT(CAST(Quote as CHAR(7))) As Quote
FROM QRTestView
WHERE Datum >= @from_val and Datum <= @to_val
GROUP BY CAST(No as CHAR(12))
) AS sel
PIVOT (
MAX(Quote)
FOR No in ('+ @colNo +')
) AS p
) AS sel2
) as ff
ORDER BY CASE WHEN Quote = ''ALL'' THEN 101 ELSE CAST(Quote as INT) END DESC'
EXEC sp_executesql @query, N'@from_val datetime, @to_val datetime', @from_val = @from, @to_val = @to
END
要理解这个问题,我将向您展示源表:
| No | Quote | Datum
| DE10101 | 100 | 2016-01-01
| DE10121 | 100 | 2016-01-02
| DE10101 | 100 | 2016-01-05
| DE22034 | 98 | 2016-01-05
| DE10101 | 98 | 2016-01-10
| DE10121 | 80 | 2016-01-10
| DE22034 | 98 | 2016-01-10
| DE22034 | 80 | 2016-01-11
| DE10101 | 100 | 2016-01-20
| DE10121 | 80 | 2016-01-21
目标表还有3个列:
| Quote | DE10101 | DE10121 | DE22034 | ALL | Bonus | Fee | Fee2 |
| 100 | 3 | 1 | 0 | 4 | 70 | 195 | 780 |
| 98 | 1 | 0 | 2 | 3 | 50 | 175 | 525 |
| 80 | 0 | 2 | 1 | 3 | -70 | 55 | 165 |
| ALL | 4 | 3 | 3 | 10 | | | 1470 |
3个新列是:Bonus, Fee, Fee2
计算如下:
加成:
WHEN 70-(100 - Quote) * 10 > -80
THEN 70-(100 - Quote) * 10
ELSE -70
费用:
Bonus + 125
费用2:
ALL * Fee
如何在存储过程中的查询变量中定义这3列和计算?
答案 0 :(得分:1)
您需要使用CTE
SET NOCOUNT ON;
DECLARE @colNo nvarchar(max)
DECLARE @SUMCols nvarchar(max)
DECLARE @query nvarchar(max)
SET NOCOUNT ON;
WITH vals AS (
SELECT DISTINCT ds.[No]
FROM QRTestView ds
)
SELECT @colNo = COALESCE(@colNo + ', ', '') + QUOTENAME([No]),
@SUMCols = COALESCE(@SUMCols + ', ', '') + 'SUM(' + QUOTENAME([No]) +')'
FROM vals
ORDER BY No
SELECT @query = N'
;WITH cte as (
SELECT *,
[Bonus] + 125 as [Fee],
([Bonus] + 125) * [ALL] as [Fee2]
FROM (
SELECT *,
CASE WHEN 70-(100 - Quote) * 10 > -80 THEN 70-(100 - Quote) * 10 ELSE -70 END as [Bonus]
FROM (
SELECT *,
'+REPLACE(@colNo,',','+')+' as [ALL]
FROM (
SELECT CAST(No as CHAR(12)) As No,
CAST(Quote as CHAR(7)) As Quote,
CAST(Quote as CHAR(7)) As Q
FROM QRTestView
WHERE Datum >= @from_val and Datum <= @to_val
) AS sel
PIVOT (
COUNT(Q)
FOR No IN ('+@colNo+')
) AS p
) AS d
) as ff
)
SELECT *
FROM (
SELECT *
FROM cte
UNION ALL
SELECT ''ALL'',
'+@SUMCols+'
SUM([ALL]),
NULL,
NULL,
SUM(Fee2)
FROM cte
) as t
ORDER BY CASE WHEN Quote = ''ALL'' THEN 101 ELSE CAST(Quote as INT) END DESC'
EXEC sp_executesql @query, N'@from_val datetime, @to_val datetime', @from_val = @from, @to_val = @to