我读了the Express.js documentation,它讨论了使用如下语法处理路由的回调:
app.get(path, callback [, callback ...])
但是,我似乎无法找到一个很好的语法示例来处理catch-all *
路由的多个回调。具体来说,路由处理程序需要:
1。)以index.html
为所有观看请求提供服务,但随后为
2.)通过返回相应的文件,为index.html
中指定的资产提供回调请求。
完成管理所有回调需要哪些特定语法,以便Express.js服务器返回每个请求的资源文件,包括JavaScript,CSS等?
当我使用以下内容时:
app.get('*', function(req, res) {
console.log('inside * route!');
if(req.accepts('html')){
console.log('req.accepts html');
console.log('req.url is: '+ req.url);
}
if(req.accepts('text/html')){
console.log('req.accepts text/html');
console.log('req.url is: ' + req.url);
}
if(req.accepts('application/json')){
console.log('req.accepts application/json');
console.log('req.url is: ' + req.url);
}
if(req.accepts('json', 'text')){
console.log('req.accepts json, text');
console.log('req.url is: ' + req.url);
}
if(req.accepts('text/javascript')){
console.log('req.accepts html');
console.log('req.url is: ' + req.url);
}
if(req.accepts('text/css')){
console.log('req.accepts text/css');
console.log('req.url is: ' + req.url);
}
res.sendFile(path.resolve('dist/client/index.html')); // load the single view file (angular will handle the front-end)
});
结果是:
1。)index.html
用于响应每种文件类型的每个请求,包括JavaScript,CSS等。
2.)条件语句不区分所请求文件的内容类型。
控制台打印出来记录这是:
App listening on port 8080
inside * route!
req.accepts html
req.url is: /
req.accepts text/html
req.url is: /
req.accepts application/json
req.url is: /
req.accepts json, text
req.url is: /
req.accepts html
req.url is: /
req.accepts text/css
req.url is: /
GET / 304 30.181 ms - -
inside * route!
req.accepts html
req.url is: /boot.css
req.accepts text/html
req.url is: /boot.css
req.accepts application/json
req.url is: /boot.css
req.accepts json, text
req.url is: /boot.css
req.accepts html
req.url is: /boot.css
req.accepts text/css
req.url is: /boot.css
inside * route!
req.accepts html
req.url is: /vendor.js
req.accepts text/html
req.url is: /vendor.js
req.accepts application/json
req.url is: /vendor.js
req.accepts json, text
req.url is: /vendor.js
req.accepts html
req.url is: /vendor.js
req.accepts text/css
req.url is: /vendor.js
inside * route!
req.accepts html
req.url is: /boot.js
req.accepts text/html
req.url is: /boot.js
req.accepts application/json
req.url is: /boot.js
req.accepts json, text
req.url is: /boot.js
req.accepts html
req.url is: /boot.js
req.accepts text/css
req.url is: /boot.js
GET /boot.css 304 2.213 ms - -
GET /vendor.js 304 2.886 ms - -
GET /boot.js 304 2.638 ms - -
作为参考,Express.js应用程序的根index.html
为:
// set up ======================================================================
var express = require('express');
var app = express(); // create our app w/ express
var port = process.env.PORT || 8080; // set the port
var morgan = require('morgan'); // log requests to the console (express4)
var bodyParser = require('body-parser'); // pull information from HTML POST (express4)
var methodOverride = require('method-override'); // simulate DELETE and PUT (express4)
app.use(express.static(__dirname + '/dist/client')); // set the static files location /public/img will be /img for users
app.use(morgan('dev')); // log every request to the console
app.use(bodyParser.urlencoded({'extended':'true'})); // parse application/x-www-form-urlencoded
app.use(bodyParser.json()); // parse application/json
app.use(bodyParser.json({ type: 'application/vnd.api+json' })); // parse application/vnd.api+json as json
app.use(methodOverride());
app.use('/scripts', express.static(__dirname + '/node_modules/'));
// load the routes
require('./router')(app);
// listen (start app with node server.js) ======================================
app.listen(port);
console.log("App listening on port " + port);
答案 0 :(得分:1)
您可以使用static files serving完成您想要做的事。
正如官方文档中所述,您只需使用以下代码即可投放所有资源(.js
,.css
等。):
app.use('/static', express.static(__dirname + '/public'));