------------------------------格式编号--------------- -------------------------------------------------- -----
- 249 webm audio only DASH audio 52k,opus @ 50k,629.08KiB
- 250 webm音频仅DASH音频69k,opus @ 70k,811.98KiB
- 171 webm audio only DASH audio 110k,vorbis @ 128k,1.27MiB
- 140 m4a仅音频DASH音频128k,m4a_dash容器,mp4a.40.2 @128k,1.56MiB
- 251 webm audio only DASH audio 138k,opus @ 160k,1.53MiB
- 278 webm 254x144 144p 82k,webm容器,vp9,13fps,仅限视频,772.69KiB
- 242 webm 400x226 240p 101k,vp9,25fps,仅限视频,884.56KiB
- 160 mp4 254x144 144p 112k,avc1.4d400c,13fps,仅限视频,1.31MiB
- 133 mp4 400x226 240p 265k,avc1.4d400d,25fps,仅视频,2.92MiB
- 17 3gp 176x144小,mp4v.20.3,mp4a.40.2 @ 24k
- 36 3gp 320x180小,mp4v.20.3,mp4a.40.2
- 18 mp4 400x226 medium,avc1.42001E,mp4a.40.2 @ 96k
- 43 webm 640x360 medium,vp8.0,vorbis @ 128k(best)
我想在像这样的程序中使用格式编号
import youtube_dl
url = "https://www.youtube.com/watch?v=BaW_jenozKc"
ydl_opts = {
'verbose': True,
'format': 'bestaudio/best', #maybe like this 'formatid'= 22
'outtmpl': '%(title)s-%(id)s.%(ext)s',
'noplaylist': True,
}
with youtube_dl.YoutubeDL(ydl_opts) as ydl:
ydl.download([url])
我该怎么做
答案 0 :(得分:1)
如果你真的想要格式22,那么确实传递format
的{{1}}密钥。如果22不可用,您可以使用22
回退到最佳视频格式:
/best