如何提高应用性能?

时间:2016-07-27 08:54:29

标签: android jdbc

我正在开发一个Android应用程序,当我选择一个片段时,我将这些代码放在“OnActivityCreated”中,例如:

 @Override
public void onActivityCreated(@Nullable Bundle savedInstanceState) {
    super.onActivityCreated(savedInstanceState);
    btnAdd = (ImageButton) getActivity().findViewById(R.id.imageButtonTime);
    txtTime = (TextView) getActivity().findViewById(R.id.textViewTime);
    txtTime.setText("");
    listView = (ListView) getActivity().findViewById(R.id.listView);
    time_control = new Time_Control(LoginActivity.db.getConnection());
    accountID = LoginActivity.Account_Id;
    calendar = Calendar.getInstance();
    mYear = calendar.get(Calendar.YEAR); // current year
    mMonth = calendar.get(Calendar.MONTH); // current month
    mDay = calendar.get(Calendar.DAY_OF_MONTH); // current day
    txtTime.setText(mDay + "/" + (mMonth + 1) + "/" + mYear);
    sDate = mYear + "-" + (mMonth + 1) + "-" + mDay;
    LoadList();

LoadList()用于从数据库中获取数据并将其放在listview上。 当我选择片段时,我的应用程序加载非常慢。无论如何我都可以做到提高性能,比如将代码放到其他位置。

感谢您的帮助!

编辑:LoadList()代码:

 public ArrayList<Time> LoadTime(int accId, String date) {
    ArrayList<Time> arrayList = new ArrayList<Time>();
    try {
        PreparedStatement query = connection.prepareStatement("exec sp_excutedtask_load ?,?");
        query.setInt(1, accId);
        query.setString(2, date);
        ResultSet resultSet = query.executeQuery();
        while (resultSet.next()) {
            int id = resultSet.getInt("ID");
            String tagName = resultSet.getString("TagName");
            String taskName = resultSet.getString("TaskName");
            int esHrs = resultSet.getInt("EsHour");
            int esMin = resultSet.getInt("EsMinute");
            int acHrs = resultSet.getInt("AcHour");
            int acMin = resultSet.getInt("AcMinute");
            String start, end;
            if (resultSet.getTime("Start") == null) {
                start = "";
            } else {
                start = resultSet.getTime("Start").toString();
            }
            if (resultSet.getTime("End") == null) {
                end = "";
            } else {
                end = resultSet.getTime("End").toString();
            }
            int run = resultSet.getInt("Running");
            int done = resultSet.getInt("Done");
            Time time = new Time(id, tagName, taskName, esHrs, esMin, acHrs, acMin, start, end, run, done);
            arrayList.add(time);
        }
    } catch (SQLException e) {
        e.printStackTrace();
    }
    return arrayList;
}

1 个答案:

答案 0 :(得分:-2)