Question

我有以下数据，我可以有3种不同的情况：

案例1：

"afield1" : "something1", "credentials" : [] , "afield2" : "something2"

案例2：

"afield1" : "something1", "credentials" : [ ["root", "toor"] ] , "afield2" = "something2"

案例3：

"afield1" : "something1", "credentials" : [ [ "admin", "support" ], [
"admin", "password" ], [ "admin", "123321" ] ] , "afield2" : "something2"

如何获取用户名和密码？

编辑：

我找到了第一种情况的愚蠢方式..但其他人是如此恭言..它不能在逗号（，）或braket（[]）上爆炸...如果有什么知道如何爆炸正确帮助或从那件事中获取价值......

Answer 1

您可以使用此代码中的preg_match和preg_match_all函数

$credentials = [];

$text = '"afield1" = "something1", "credentials" : [ [ "admin", "support" ], ["admin", "pass]word" ], [ "admin", "123321" ] ] , "afield2" = "something2"';

preg_match('/"credentials" : \[(.*?)\] ,/i', $text, $matches);
preg_match_all('/\[[ ]?"(.*?)"[ ]?\]/i', $matches[1], $matches2);

foreach ($matches2[1] as $match) {
    preg_match_all('/"(.*?)"/i', '"' . $match . '"', $matches3);

    $credential = ['login' => $matches3[1][0], 'password' => $matches3[1][1]];
    $credentials[] = $credential;
}

var_dump($credentials);

在ouptut上你可以看到

array(3) {
  [0]=>
  array(2) {
    ["login"]=>
    string(5) "admin"
    ["password"]=>
    string(7) "support"
  }
  [1]=>
  array(2) {
    ["login"]=>
    string(5) "admin"
    ["password"]=>
    string(8) "pass]word"
  }
  [2]=>
  array(2) {
    ["login"]=>
    string(5) "admin"
    ["password"]=>
    string(6) "123321"
  }
}

此代码适用于您问题中的其他示例。

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