Question

我没有通过Google搜索控制台API获得结果。在调用函数时给予它未捕获的例外＆＃39; Google_Exception＆＃39;消息＆＃39;（查询）缺少必需的参数：＆＃39; siteUrl＆＃39; SITEURL /测试-AAP / SRC /谷歌/服务/ Resource.php：165

 $timestamp = strtotime( '1 month ago' );
            $query = new Google_Service_Webmasters_UrlCrawlErrorCountsPerType();
            $query->setCategory("authPermissions");    
            $filter = new Google_Service_Webmasters_UrlCrawlErrorCount();
            $filter->setCount('5');
            $filter->setTimestamp($timestamp);

            $check = $query->setEntries(array($filter));
            $query->setPlatform("web");
            $getSearchresponseOb    = $service->urlcrawlerrorscounts->query('siteurl','soft404','true','web');
            $getSearchresponse      = $getSearchresponseOb->toSimpleObject();
            print_r($getSearchresponse);

Answer 1

我认为错误信息很明显。根据Google的文档https://developers.google.com/webmaster-tools/v3/urlcrawlerrorscounts/query，“siteURL”应该是一个网址（例如http://www.example.com/），因此你应该有这样的内容：

$check = $query->setEntries(array($filter));
$query->setPlatform("web");
$getSearchresponseOb = $service->urlcrawlerrorscounts->query('**http://www.example.com**','soft404','true','web');
$getSearchresponse = $getSearchresponseOb->toSimpleObject();
print_r($getSearchresponse);

Google搜索控制台API - UrlCrawlErrorCountsPerType

1 个答案: