Question

Python3.5 Sql Server 2012 Standard

包是pypyodbc

本守则有效

myConnection = pypyodbc.connect('Driver={SQL Server};'
                                'Server=myserver;'
                                'Database=mydatabase;'
                                'TrustedConnection=yes')
myCursor = myConnection.cursor()
sqlstr = ("Select * From DB.Table1 Where DB.Table1.Date <= '7/21/2016'")
myCursor.execute(sqlstr)
results = myCursor.fetchall()

但是，Date必须是用户传入的变量。我为sqlstr做了几个mod但在myCursor.execute上继续出错：＆＃34; TypeError：期望的字节或整数地址而不是tuple实例＆＃34;

sqlstr = ("Select * From DB.Table1 Where DB.Table1.Date <= %s", '7/21/2016')

错误

sqlstr = ("Select * From DB.Table1 Where DB.Table1.Date <= '%s'", '7/21/2016')

错误

sqlstr = ("Select * From DB.Table1 Where DB.Table1.Date <= ?", "'7/21/2016'")

错误

var1 = "'7/21/2016'"
sqlstr = ("Select * From DB.Table1 Where DB.Table1.Date <= %s", var1)

还有几个。但是，我确信有一种正确的方法......

感谢您的帮助！

Answer 1

我确信有一种正确的方法

是的，它是参数化查询：

date_var = datetime(2016, 7, 21)
sql = """\
SELECT [ID], [LastName], [DOB] FROM [Clients] WHERE [DOB]<?
"""
params = [date_var]  # list of parameter values
crsr.execute(sql, params)
for row in crsr.fetchall():
    print(row)

如何在Python中将日期变量传递给SQL查询

1 个答案: