Question

无论请求类型如何，我都希望将中间件应用于路由。目前我有：

router.route('/campaigns')
    .get(restrictTo('advertiser'), restrictTo('admin'), queries.getCampaigns)
    .post(restrictTo('advertiser'), restrictTo('admin'), queries.createCampaign);

我想要像：

router.route('/campaigns', restrictTo('advertiser'), restrictTo('admin'))
    .get(queries.getCampaigns)
    .post(queries.createCampaign);

但这似乎不起作用。

Answer 1

您应该可以像.use()那样使用：

router.route('/campaigns')
  .use(restrictTo('advertiser'), restrictTo('admin'))
  .get(queries.getCampaigns)
  .post(queries.createCampaign);

或：

router.route('/campaigns')
  .use(restrictTo('advertiser'))
  .use(restrictTo('admin'))
  .get(queries.getCampaigns)
  .post(queries.createCampaign);

Answer 2

您可以使用.all()

示例：

 router.route('/campaigns')
      .all(yourmiddleware)
      .get(function (req, res, next) {
            // your function ...
      })

对我有用。

Answer 3

快速文档说，您可以这样做：

app.use('/user/:id', function (req, res, next) {
  console.log('Request URL:', req.originalUrl)
  next()
}, function (req, res, next) {
  console.log('Request Type:', req.method)
  next()
})

将/user/:id替换为所需的路径。

来源：https://expressjs.com/en/guide/using-middleware.html

应用中间件在Express

3 个答案: