我需要实现动态列表视图。 我已经用数组和静态方式创建了它,但我需要添加一个按钮,在网格中创建新元素并单击listner。 如果我从数组切换到列表,它将是一个解决方案? 这是我的代码,有人可以给我一些帮助吗?
网格视图:
<GridView xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:horizontalSpacing="-10dp"
tools:context="com.example.giovanni.mainapp_drawer.Activities.MainActivity"
android:orientation="vertical"
android:columnWidth="160dp"
android:fadeScrollbars="true"
android:gravity="center"
android:numColumns="2"
android:stretchMode="columnWidth"
android:id="@+id/gv"
</GridView>
BUTTON ADAPTER:
public class RoomsBtnAdapter extends BaseAdapter{
private Context context;
private final String[] strings;
private final int[] colors;
public RoomsBtnAdapter(Context context, String[] strings, int[] colors) {
this.context = context;
this.strings = strings;
this.colors = colors;
}
public View getView(int position, View convertView, ViewGroup parent) {
LayoutInflater inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View gridView;
if (convertView == null) {
gridView = new View(context);
gridView = inflater.inflate(R.layout.room_btn, null);
Button btn = (Button) gridView.findViewById(R.id.roomBtn);
btn.setText(strings[position]);
btn.setBackgroundResource(colors[position]);
} else {
gridView = (View) convertView;
}
return gridView;
}
@Override
public int getCount() {
return strings.length;
}
@Override
public Object getItem(int position) {
return null;
}
@Override
public long getItemId(int position) {
return 0;
}
}
网格视图的片段:
public class RoomsFragment extends Fragment {
public int[] colors = {R.color.colorRoom1, R.color.colorRoom2, R.color.colorRoom3, R.color.colorRoom4, R.color.colorRoom5, R.color.colorRoom6, R.color.colorRoom7};
public String[] strings = {"Conversare", "Giocare (videogames)", "Break", "Business", "Compagni di viaggio", "Aperitivo", "Chiacchiere e caffè"};
public RoomsFragment() {
// Required empty public constructor
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
return inflater.inflate(R.layout.fragment_rooms, container, false);
}
@Override
public void onViewCreated(View view, Bundle savedInstanceState) {
final GridView gridView = (GridView) getActivity().findViewById(R.id.gv);
gridView.setAdapter(new RoomsBtnAdapter(getContext(), strings, colors));
gridView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
switch (position) {
case 0:
Log.d("click", "click");
case 1:
}
}
});
}
}
答案 0 :(得分:0)
你做得很好!是的,有一个解决方案。关键方法是adapter.notifyDataSetChanged();如果你调用这个notifyDataSetChanged,那么适配器会尝试&#34;重绘&#34; ListView,所以如果您对数据源进行任何更改(在这种情况下,您将向列表中添加一个元素),您将看到不同数量的单元格。
所以你需要按照以下步骤操作:
1-替换列表的字符串[]
2-保留对创建的适配器的引用
3-每次进行更改时调用此适配器上的notifyDataSetChanged()(此方法应在UI线程中调用)
最终代码应如下所示:
final GridView gridView = (GridView) getActivity().findViewById(R.id.gv);
final RoomsBtnAdapter adapter = new RoomsBtnAdapter(getContext(), strings, colors);
gridView.setAdapter(adapter);
gridView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
switch (position) {
case 0:
strings.add("New String");
adapter.notifyDataSetChanged(); //This is the key ingredient
case 1:
}
}
});