Question

我想在加载第二个无模式窗体（button3）时禁用主窗体上的按钮（Form2），然后在关闭无模式窗体时重新启用该按钮。

以下是我尝试的内容：

private void button3_Click(object sender, EventArgs e)
{
    Form2 p = new Form2(label1.Text);
    p.Show();

    if (p.Shown)
        this.button3.Click += new System.EventHandler(this.button3_Click);
    else
        this.button3.Click -= new System.EventHandler(this.button3_Click);
}

Answer 1

实现此目标的最佳方法是在显示button3之前停用Form2，并使用FormClosed上的Form2事件重新启用button3表格关闭后：

public partial class Form1 : Form
{
    ...

    private void button3_Click(object sender, EventArgs e)
    {
        // Instantiate the form and assign the FormClosed event
        var form = new Form2(label1.Text);
        form.FormClosed += Form2_FormClosed;

        // Disable button3
        button3.Enabled = false;

        // Show the form
        form.Show();
    }

    // Occurs when Form2 is closed
    private void Form2_FormClosed(object sender, FormClosedEventArgs e)
    {
        // Re-enable button3
        button3.Enabled = true;
    }
}

另一种方法，它将lambda表达式赋给FormClosed事件：

private void button3_Click(object sender, EventArgs e)
{
    // Instantiate the form
    var form = new Form2(label1.Text);

    // Assign a lambda method to the FormClosed event to re-enable button3
    form.FormClosed += (s, a) => button3.Enabled = true;

    // Disable button3
    button3.Enabled = false;

    // Show the form
    form.Show();
}

Answer 2

我做了类似的事情，我不确定你想要做什么，但也许它会帮助你。

public partial class Form2 : Form
{ 
private void button3_Click(object sender, EventArgs e)
{
    Button3.Enabled = false;
    Form2 p = new Form2(label1.Text);

    p.ShowDialog();


    //the code will stop here until you finish your work on form2

     Button3.Enabled=true;
}

它适用于我。

但如果你的form3只是一个短标签使用：

Button3.Enabled= false;
MessageBox.show ("blabla");
Button3.Enabled=true;

在加载表单时禁用按钮，在表单关闭时启用

2 个答案: