Question

Node.js readline-sync暂停我的服务器，如果服务器正在等待命令，我怎么能这样做呢？打印我的信息？

也许有多线程的东西，或2 cmd但不太好。

这是我的服务器代码：

'use strict';

var http = require('http'),
    fs = require('fs');
var PORT = 8080;
var requestIp = require('request-ip');
var os = require('os');
var hostname = os.hostname();
var readlineSync = require('readline-sync');

//get client ip
var ipMiddleware = function(request, response) {
    var clientIp = requestIp.getClientIp(request);
    return clientIp.slice(7);
};

//print function
function msg(msg){
    msg = msg.charAt(0).toUpperCase() + msg.slice(1);
    console.log("> "+msg);
    console.log();
}

//command function
function inpt(){
    var command = readlineSync.question('> ');//this is the line that freezing all
    console.log();
    if(command === "exit" || command === "stop" || command === "end" ){
        msg(command+"ing server...");
        process.exit();
    }if(command.substring(0, 14) === "switch port to " && command.length === 18 && parseInt(command.substring(14,18)).isInteger > 0){
        PORT = parseInt(command.substring(14,18));
        msg("port changed to "+PORT);
        http.createServer(onRequest).listen(PORT);
        msg("LAN server running on "+addresses[0]+":"+PORT);
    }

    else{
        msg("sorry but "+command+" is an unknown command.");
    }
    //after receiving command its's ask again for input
    inpt();
}

//get server ip
var interfaces = os.networkInterfaces();
var addresses = [];
for (var k in interfaces) {
    for (var k2 in interfaces[k]) {
        var address = interfaces[k][k2];
        if (address.family === 'IPv4' && !address.internal) {
            addresses.push(address.address);
        }
    }
}

//404 Response
function send404Response(request,response) {
    msg("Error 404 "+ipMiddleware(request,response));
    response.writeHeader(404, {"Content-Type": "text/html"});  
    fs.createReadStream('./404.html').pipe(response);
}

//write html file to client by name
function sendFileResponse(name,request,response)    {
    msg(name+" page "+ipMiddleware(request,response));
    response.writeHeader(200, {"Content-Type": "text/html"});  
    fs.createReadStream('./'+name+'.html').pipe(response);
}

//handle request
function onRequest(request, response) {
    if(request.method == 'GET' && request.url == '/'){
        msg("Home page "+ipMiddleware(request,response));
        response.writeHeader(200, {"Content-Type": "text/html"});  
        fs.createReadStream('./index.html').pipe(response);
    }else if(request.url.length > 1){
        var name = request.url.slice(1);
        if(fs.existsSync("./"+name+".html")){
            sendFileResponse(name,request,response);
        }else{
            send404Response(request,response);
        }
    }else{
        send404Response(request,response);
    }
}

//start
msg("Server ip: "+addresses[0]);
msg("Hostname: "+hostname);
http.createServer(onRequest).listen(PORT);
msg("LAN server running on "+addresses[0]+":"+PORT);
//on start the cmd will ask for commands
inpt();

Answer 1

readlineSync()是同步的。根据定义，一切都将等到该呼叫结束。如果您无法获得该行为，请使用readline()。

请参阅https://nodejs.org/api/readline.html#readline_rl_question_query_callback

您可以尝试这样的事情：

    function inpt(){
    readline.question('> ', function( command ) {
      console.log();
      if(command === "exit" || command === "stop" || command === "end" ){
          msg(command+"ing server...");
          process.exit();
      }if(command.substring(0, 14) === "switch port to " && command.length === 18 && parseInt(command.substring(14,18)).isInteger > 0){
          PORT = parseInt(command.substring(14,18));
          msg("port changed to "+PORT);
          http.createServer(onRequest).listen(PORT);
          msg("LAN server running on "+addresses[0]+":"+PORT);
      }

      else{
          msg("sorry but "+command+" is an unknown command.");
      }
      //after receiving command its's ask again for input
      inpt();
  }
});

您可能需要稍微修改内部，我只是将其余代码放入回调中，因此在命令分配后它将运行。

Node.js readline-sync冻结我的服务器（windows）

1 个答案: