我无法使用awk
获取完整字符串。例如,
File.txt有,
C1 C2 C3
A B 'A B C'
C D 'D E F'
如果我使用以下代码,
awk '{print $1 "," $3}' File.txt
我的输出为,
A,'A
C,'D
预期输出是,
A,'A B C'
C,'D E F
答案 0 :(得分:1)
select top 1
a.IN_Notification_ID,
a.DI_Surrogate_ID,
a.IN_Ref_Content_ID,
a.IN_Name,
a.IN_Description,
a.IN_Category,
a.IN_Rank,
a.IN_Publish_Date,
a.IN_URL_EN,
a.IN_URL_FR,
a.IN_URL_NAME_EN,
a.IN_URL_NAME_FR,
a.IN_HEADER_EN,
a.IN_HEADER_FR,
a.IN_BODY_EN,
a.IN_BODY_FR,
a.IN_ACTION_COMPLETE_URL_EN,
a.IN_ACTION_COMPLETE_URL_FR,
1 as 'IN_COMPLETE',
getdate() as 'ET_LAST_MODIFIED_DATE'
from CXXXXXXX.Important_Notices_Inbox a with (nolock)
inner join CXXXXXXX.IGO_PROFILES b with (nolock) on a.DI_Surrogate_ID = b.email
inner join CXXXXXXX.PI_CONTENTVIEWS c on b.[user_id] = c.[user_id] and a.IN_Ref_Content_ID = c.content_id
where c.[timestamp] > a.[Date_Added]
order by c.[timestamp] desc
答案 1 :(得分:0)
awk
的默认分隔符是空格。由于您的数据有标签,因此您应使用'\ t'
<强> file.txt的强>
A B 'A B C'
C D 'D E F'
awk命令
awk '{BEGIN FS="\t"}{print $1 "," $3}' <file.txt
<强>输出强>
A,'A B C'
C,'D E F'