我有一个包含TextFields的ViewController,我需要将这些值发送到专用的HTTP服务。 我主要担心的是编码类型,因为这个应用程序是法语版,可能包含一些重音符号('é','è'等等...)但我还需要正确格式化我的字段,因为它可能包含空格以及....
我尝试使用不同的方法,但我在服务器端仍然有错误的编码。
这是我的代码示例:
let url_to_request = "http://11.22.33.44:8080/SRV/addRepertoire"
let params = "owner=\(User.sharedInstance.email)&adresse=\(adresse.text!)&nom=\(nom.text!)&telephone=\(telephone.text!)&commentaires=\(commentaires.text!)"
let tmp_url = url_to_request + "?" + params
let final_url = tmp_url.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLQueryAllowedCharacterSet())!
print("URL addRepertoire: \(final_url)")
例如,字段“nom”包含“bébé”,其编码为“b%C4%82%C5%A0b%C4%82%C5%A0”,而我的服务器期待“b%E9b%E9”
EDIT2:
我尝试使用以下内容:
b%C3%83%C2%A9b%C3%83%C2%A9, diplayed bébé instead of bébé
但结果仍然是:
def game():
#This selects 5 community cards from the pick_community function
community = pick_community(5)
card_4 = community[3]
card_5 = community[4]
first_3 = community[0:3]
return first_3
river = raw_input("If you are done with the round hit enter:" )
try:
if river =="":
return card_4
except:
print "Dont cheat man"
exit()
答案 0 :(得分:5)
extension String {
func stringByAddingPercentEncodingForISOLatin1() -> String? {
let allowedCharacterSet = NSCharacterSet(charactersInString:
"0123456789"
+ "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
+ "abcdefghijklmnopqrstuvwxyz"
+ "_-.~"
+ "=&" //You'd better remove this and encode each param.
)
if let data = self.dataUsingEncoding(NSISOLatin1StringEncoding) {
var result = ""
for i in 0..<data.length {
let ch = UnsafePointer<UInt8>(data.bytes)[i]
if ch >= 0x80 || !allowedCharacterSet.characterIsMember(unichar(ch)) {
result += String(format: "%%%02X", ch)
} else {
result.append(UnicodeScalar(ch))
}
}
return result
} else {
return nil
}
}
}
"bébé".stringByAddingPercentEncodingForISOLatin1()! //->"b%E9b%E9"
总是使用UTF-8表示,所以我担心您可能需要自己动手。
{{1}}
答案 1 :(得分:0)
以下是Swift 4中的解决方案:
extension String {
// Url percent encoding according to RFC3986 specifications
// https://tools.ietf.org/html/rfc3986#section-2.1
func urlPercentEncoded(withAllowedCharacters allowedCharacters:
CharacterSet, encoding: String.Encoding) -> String {
var returnStr = ""
// Compute each char seperatly
for char in self {
let charStr = String(char)
let charScalar = charStr.unicodeScalars[charStr.unicodeScalars.startIndex]
if allowedCharacters.contains(charScalar) == false,
let bytesOfChar = charStr.data(using: encoding) {
// Get the hexStr of every notAllowed-char-byte and put a % infront of it, append the result to the returnString
for byte in bytesOfChar {
returnStr += "%" + String(format: "%02hhX", byte as CVarArg)
}
} else {
returnStr += charStr
}
}
return returnStr
}
}
用法:
"aouäöü!".urlPercentEncoded(withAllowedCharacters: .urlQueryAllowed,
encoding: .isoLatin1)
// Results in -> "aou%E4%F6%FC!"
答案 2 :(得分:0)
对于Objective-C:
/login.py
subprocess.popen('python','main.py')
quit()
/main.py
subprocess.popen('python','login.py')