Question

如果数据在模态中，我想要在mysql数据库中插入细节时要求一些帮助。我一直在努力完成我的这个样本项目，希望我将来可以将它作为一个组合。这是模态代码。

main.php

<div class="modal fade" id="registrationModalold" role="dialog">
  <div class="modal-dialog">
  <!-- Modal content-->
    <div class="modal-content">
      <!--<form action="functions/actions.php" method="POST">-->
      <div class="modal-header">
        <button type="button" class="close" data-dismiss="modal">&times;</button>
          <h4 class="modal-title">Enrollment Details</h4>
      </div>
      <div class="modal-body">
        <form method="post" action="functions/actions.php">
          <h4 class="modal-title">Personal Information</h4>
          <div class="row">
          <div class="col-lg-6 col-xs-6">
            <label for="usr">Name:</label>
            <select class="form-control" name="courses">
            <?php 
              include 'ini/db.php'; //connect to database
              $sql = "SELECT distinct student_name FROM tbl_students";
              $res = mysqli_query($conn,$sql);
              echo "<option>---SELECT STUDENT---</option>";

              while ($row = mysqli_fetch_array($res)){
                echo "<option value=Course".$row['student_name'].">" . $row['student_name'] . "</option>";
              }
            ?>
            </select>
          </div><!-- ./col -->
          <div class="col-lg-6 col-xs-6">
            <label for="usr">Addres:</label>
            <input type="text" class="form-control" id="fullname">
          </div><!-- ./col -->
        </div>
        <div class="row">
          <div class="col-lg-3 col-xs-6">
            <label for="usr">Contact:</label>
            <input type="text" class="form-control" id="fullname">
          </div><!-- ./col -->
          <div class="col-lg-3 col-xs-6">
            <label for="usr">BirthDate:</label>
            <input type="text" class="form-control" id="fullname">
          </div><!-- ./col -->
          <div class="col-lg-3 col-xs-6">
            <label for="usr">Birth Place:</label>
            <input type="text" class="form-control" id="fullname">
          </div><!-- ./col -->
          <div class="col-lg-3 col-xs-6">
            <label for="usr">Gender:</label>
            <select class="form-control">
              <option id="male">Male</option>
                <option id="female">Female</option>
            </select>
          </div><!-- ./col -->
        </div>
        </br></br>
        <h4 class="modal-title">Other Information</h4>
          <div class="row">
            <div class="col-lg-6 col-xs-6">
              <label for="usr">Course:</label>
                <select class="form-control" name="courses">
                <?php 
                  include 'ini/db.php'; //connect to database
                  $sql = "SELECT crs_id,crs_name FROM tbl_courses";
                  $res = mysqli_query($conn,$sql);
                  echo "<option>---SELECT COURSE---</option>";

                  while ($row = mysqli_fetch_array($res)){
                    echo "<option value=Course".$row['crs_id'].">" . $row['crs_name'] . "</option>";
                  }
                ?>
                </select>
              </div><!-- ./col -->
              <div class="col-lg-6 col-xs-6">
                <label for="usr">Major:&nbsp<font color="red" size="2"><i>optional</i></font></label>
                <input type="text" class="form-control" id="fullname">
              </div><!-- ./col -->
            </div>
            <div class="row">
              <div class="col-lg-3 col-xs-6">
                <label for="usr">Mother's Name:</label>
                <input type="text" class="form-control" id="fullname">
              </div><!-- ./col -->
              <div class="col-lg-3 col-xs-6">
                <label for="usr">Mother's Occupation:</label>
                <input type="text" class="form-control" id="fullname">
              </div><!-- ./col -->
              <div class="col-lg-3 col-xs-6">
                <label for="usr">Father's Name:</label>
                <input type="text" class="form-control" id="fullname">
              </div><!-- ./col -->
              <div class="col-lg-3 col-xs-6">
                <label for="usr">Father's Occupation:</label>
                <input type="text" class="form-control" id="fullname">
              </div><!-- ./col -->
            </div>
          </div>
        <div class="modal-footer">
          <button name="btnregister" action="functions/actions.php" type="button" class="btn btn-default">Save</button>
          <button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
         </div>
       </form>
     </div>
   </div>
 </div>
</div>

正如你可以看到那里有一个按钮那里有一个指向我的actions.php的按钮，它位于另一个文件夹中，这是一个函数文件夹。但是当我点击时没有任何反应。

这里是action.php：

if (isset($_POST['btnregisters'])) {
    echo "ASASASASASASASASASASAS";
    die("asdsadsada");
}

Answer 1

正如你所看到的那样，有一个按钮指向我的actions.php，它位于另一个文件夹中，该文件夹是函数文件夹。但是，当我点击没有任何反应时
<button name="btnregister" action="functions/actions.php" type="button" class="btn btn-default">Save</button>

你说type="button"。整个过程就是让按钮不执行任何操作（因此您可以将JavaScript事件处理程序绑定到它）。

把它拿出来，让它成为提交表格的默认（type="submit"）。

Answer 2

请注意，提交按钮设置为按钮类型=＆＃34;按钮＆＃34;

 <button name="btnregister" action="functions/actions.php" type="button" class="btn btn-default">Save</button>

将其更改为：

<button name="btnregister" action="functions/actions.php" type="submit" class="btn btn-default">Save</button>

Answer 3

您已在表单标记中定义了操作属性。动作属性不适用于按钮，所以不要在那里写。

要提交表单，您需要提交按钮，然后从＆＃34;按钮＆＃34;更改保存按钮的类型。提交＆＃34;提交＆＃34; 它应该像

<button name="btnregister" type="submit" class="btn btn-default">Save</button>

在模式

3 个答案: