下面是我的代码,我在堆栈溢出和codeigniter用户指南中引用了所有示例。我仍然无法解决这个问题
public function send()
{
$config['protocol'] = 'smtp';
$config['smtp_crypto'] = 'ssl';
$config['smtp_host'] = 'smtp.gmail.com';
$config['smtp_port'] = '465';
$config['smtp_user'] = '**********@gmail.com';
$config['smtp_pass'] = '********';
$config['mailtype'] = 'html';
$config['charset'] = 'utf-8';
$config['newline'] = "\r\n";
$config['wordwrap'] = TRUE;
$config['smtp_timeout'] = 30;
$this->email->initialize($config);
$this->email->from('uvizag@gmail.com', 'admin');
$this->email->to('siddharthaesunuri@gmail.com, siddhu.php@gmail.com');
$this->email->subject('Registration Verification:');
$message = "Thanks for signing up! Your account has been created...!";
$this->email->message($message);
if ( ! $this->email->send()) {
show_error($this->email->print_debugger());
}
}
如何解决此错误?可以取悦我了
答案 0 :(得分:5)
你试试这个吗?
$config = Array(
'protocol' => 'smtp',
'smtp_host' => 'ssl://smtp.googlemail.com',
'smtp_port' => 465,
'smtp_user' => 'xxx',
'smtp_pass' => 'xxx',
'mailtype' => 'html',
'charset' => 'iso-8859-1'
);
$this->load->library('email', $config);
$this->email->set_newline("\r\n");
// Set to, from, message, etc.
$result = $this->email->send();
并确保您已设置电子邮件帐户 {{3}}
答案 1 :(得分:4)
$this->email->set_newline("\r\n");
如果没有该行,gmail就错误的用户/密码投诉:|
此致
答案 2 :(得分:-1)
我很难让这个原生CI功能发挥作用。我必须实现一个外部库:PHPMailer。检查this thread。