Question

我正在玩RxJava retryWhen运算符。在互联网上发现它很少，唯一值得提及的是this。这也无法探索我想要理解的各种用例。我还投入异步执行并使用后退重试以使其更加真实。

我的设置很简单：我有一个类ChuckNorrisJokesRepository，可以从JSON文件中返回随机数量的Chuck Norris笑话。我正在测试的课程是ChuckNorrisJokesService，如下所示。我感兴趣的用例如下：

第一次尝试成功（无重试）
1次重试后失败
尝试重试3次，但第2次成功，因此不会第3次重试
第三次重试成功

注意：该项目可在GitHub上找到。

ChuckNorrisJokesService.java ：

@Slf4j
@Builder
public class ChuckNorrisJokesService {
    @Getter
    private final AtomicReference<Jokes> jokes = new AtomicReference<>(new Jokes());

    private final Scheduler scheduler;
    private final ChuckNorrisJokesRepository jokesRepository;
    private final CountDownLatch latch;
    private final int numRetries;
    private final Map<String, List<String>> threads;

    public static class ChuckNorrisJokesServiceBuilder {
        public ChuckNorrisJokesService build() {
            if (scheduler == null) {
                scheduler = Schedulers.io();
            }

            if (jokesRepository == null) {
                jokesRepository = new ChuckNorrisJokesRepository();
            }

            if (threads == null) {
                threads = new ConcurrentHashMap<>();
            }

            requireNonNull(latch, "CountDownLatch must not be null.");

            return new ChuckNorrisJokesService(scheduler, jokesRepository, latch, numRetries, threads);
        }
    }

    public void setRandomJokes(int numJokes) {
        mergeThreadNames("getRandomJokes");

        Observable.fromCallable(() -> {
            log.debug("fromCallable - before call. Latch: {}.", latch.getCount());
            mergeThreadNames("fromCallable");
            latch.countDown();

            List<Joke> randomJokes = jokesRepository.getRandomJokes(numJokes);
            log.debug("fromCallable - after call. Latch: {}.", latch.getCount());

            return randomJokes;
        }).retryWhen(errors ->
                errors.zipWith(Observable.range(1, numRetries), (n, i) -> i).flatMap(retryCount -> {
                    log.debug("retryWhen. retryCount: {}.", retryCount);
                    mergeThreadNames("retryWhen");

                    return Observable.timer(retryCount, TimeUnit.SECONDS);
                }))
                .subscribeOn(scheduler)
                .subscribe(j -> {
                            log.debug("onNext. Latch: {}.", latch.getCount());
                            mergeThreadNames("onNext");

                            jokes.set(new Jokes("success", j));
                            latch.countDown();
                        },
                        ex -> {
                            log.error("onError. Latch: {}.", latch.getCount(), ex);
                            mergeThreadNames("onError");
                        },
                        () -> {
                            log.debug("onCompleted. Latch: {}.", latch.getCount());
                            mergeThreadNames("onCompleted");

                            latch.countDown();
                        }
                );
    }

    private void mergeThreadNames(String methodName) {
        threads.merge(methodName,
                new ArrayList<>(Arrays.asList(Thread.currentThread().getName())),
                (value, newValue) -> {
                    value.addAll(newValue);

                    return value;
                });
    }
}

为简洁起见，我只展示第一个用例的Spock测试用例。有关其他测试用例，请参阅我的GitHub。

def "succeeds on 1st attempt"() {
    setup:
    CountDownLatch latch = new CountDownLatch(2)
    Map<String, List<String>> threads = Mock(Map)
    ChuckNorrisJokesService service = ChuckNorrisJokesService.builder()
            .latch(latch)
            .threads(threads)
            .build()

    when:
    service.setRandomJokes(3)
    latch.await(2, TimeUnit.SECONDS)

    Jokes jokes = service.jokes.get()

    then:
    jokes.status == 'success'
    jokes.count() == 3

    1 * threads.merge('getRandomJokes', *_)
    1 * threads.merge('fromCallable', *_)
    0 * threads.merge('retryWhen', *_)
    1 * threads.merge('onNext', *_)
    0 * threads.merge('onError', *_)
    1 * threads.merge('onCompleted', *_)
}

这失败了：

Too few invocations for:

1 * threads.merge('fromCallable', *_)   (0 invocations)
1 * threads.merge('onNext', *_)   (0 invocations)

我期待的是fromCallable被调用一次，成功，onNext被调用一次，然后是onCompleted。我错过了什么？

P.S。：完全披露 - 我也在RxJava GitHub上发布了这个问题。

Answer 1

经过几个小时的故障排除并在ReactiveX会员David Karnok的帮助下解决了这个问题。

retryWhen是一个复杂的，甚至是错误的运营商。官方文档和至少一个答案使用range运算符，如果没有重试，则立即完成。请与David Karnok见discussion。

我的GitHub上提供了以下测试用例的代码：

第一次尝试成功（无重试）
1次重试后失败
尝试重试3次，但第2次成功，因此不会第3次重试
第三次重试成功

RxJava重试当奇怪的行为

1 个答案: