这是我的表格。
通知表
+----+----------------+--------+
| Id | NotificationId | Status |
+----+----------------+--------+
| 1 | 1 | Read |
+----+----------------+--------+
UserNotification Table
NotificationId
如果UserNotification
表中存在+----+-------------+
| Id | Subject |
+----+-------------+
| 2 | Hello World |
| 3 | Pls Help |
+----+-------------+
,我想查询通知表而不包含数据
我想要结果:
通知表
public static Color ColorFromGuid(UUID id)
{
var values = id.ToByteArray().Select(b => (int)b);
int red = values.Take(5).Sum() % 255;
int green = values.Skip(5).Take(5).Sum() % 255;
int blue = values.Skip(10).Take(5).Sum() % 255;
Color color = Color.FromArgb(200, red, green, blue);
return color;
}
答案 0 :(得分:3)
<强>查询强>
SELECT * FROM Notification n
WHERE NOT EXISTS(
SELECT 1 FROM UserNotification u
WHERE n.Id = u.NotificationId
);
sql fiddle demo
答案 1 :(得分:2)
您可以不在
中使用select Id,Subject from notificationTable where Id not in (select Id from userNotificationTable) ;
答案 2 :(得分:1)
您也可以使用JOIN
:
SELECT n.*
FROM Notification n
JOIN UserNotification un
ON n.Id <> un.NotificationId
答案 3 :(得分:1)
答案 4 :(得分:1)
您可以通过NULL
SELECT N.Id, N.Subject
FROM `Notification` N
LEFT JOIN `UserNotification` U ON U.NotificationId = N.Id
WHERE U.NotificationId IS NULL
检查来实现此目的:
{
"response_code": 200,
"error": false,
"train_name": "KCG YPR EXP",
"train_num": "17603",
"pnr": "1234567890",
"failure_rate": 19.346153846153847,
"doj": "20-8-2015",
"chart_prepared": "Y",
"class": "SL",
"total_passengers": 2,
"train_start_date": {
"month": 8,
"year": 2015,
"day": 20
},
"from_station": {
"code": "KCG",
"name": "KACHEGUDA"
},
"boarding_point": {
"code": "KCG",
"name": "KACHEGUDA"
},
"to_station": {
"code": "YPR",
"name": "YESVANTPUR JN"
},
"reservation_upto": {
"code": "YPR",
"name": "YESVANTPUR JN"
},
"passengers": [
{
"no": 1,
"booking_status": "S7,58,GN",
"current_status": "S7,58",
"coach_position": 9
},
{
"no": 2,
"booking_status": "S7,59,GN",
"current_status": "S7,59",
"coach_position": 9
}
]
}
答案 5 :(得分:0)
使用NOT IN
Select * from Notification where id NOT IN (SELECT id FROM UserNotification)
这个sql将有助于获取数据
答案 6 :(得分:0)
SELECT n.Id, n.Subject FROM Notification n
LEFT JOIN UserNotification nu on nu.NotificationId = n.id
WHERE nu.id IS NULL
答案 7 :(得分:0)
您想要返回用户通知中没有的通知
试试这个:
select Id,Subject
from Notification
where
id not in (
select distinct NotificationId from UserNotification
)