我的角色是动态的,他们的用户权限也是动态的。我有两种方法来验证用户是否有权访问特定页面。
方法1
class BaseController extends Controller
{
public function __construct() {
if(!\Auth::user()->IsPredefined) {
$result = $this->ValidateAuthorization();
if(!$result) {
\Auth::logout();
return redirect()->route("login");
}
}
}
private function ValidateAuthorization() {
$ActionName = \Route::getCurrentRoute()->getPath();
switch ($ActionName) {
case "ChangePassword":
$ModuleID = ModuleEnum::AccountManagemenet;
$ActionID = AccountActionEnum::ChangePassword;
return CheckUsePermissions($ModuleID, $ActionID);
}
}
private function CheckUsePermissions($ModuleID, $ActionID) {
$User = MySession::UserPermissions();
foreach($User->UserRolePermissions as $UserRolePermission) {
$CurrentActionID = $UserRolePermission->RolePermission->Permission->ActionID;
$CurrentModuleID = $UserRolePermission->RolePermission->Permission->ModuleID;
if($CurrentActionID == $ActionID && $CurrentModuleID == $ModuleID &&
$UserRolePermission->IsActive == true) {
return true;
}
}
return false;
}
}
方法2
在Request class中使用Authorize方法
public function authorize()
{
return true;
}
混乱
答案 0 :(得分:0)
您应该使用中间件并在路由中使用
library(spatstat)
X <- ppp(Particles$X, Particles$Y, c(0, imageSizeX), c(0, imageSizeY))
plot(density(X), xlim = c(1, imageSizeX), ylim = c(imageSizeY, 0))
plot(X, axes = TRUE, xlim = c(1, imageSizeX), ylim = c(imageSizeY, 0), add = T)
axis(1)
axis(2, las = 2)
或者您可以在每个控制器构造函数中使用
Route::group(['middleware' => ['auth', 'admin']], function () { });
像
这样的管理中间件public function __construct()
{
$this->middleware('auth');
$this->middleware('admin');
}
答案 1 :(得分:0)
对于动态角色我做这样的事情:
假设我有以下权限:
现在Super Admin
(显然拥有上述所有权限的用户)可以创建一个角色,例如Hotel Manager
并仅为Manage Hotels
分配权限。
现在有一条路线:
Route::get('/admin/hotels', 'HotelsController@index')->name('admin.hotels.index');
我会把它放在一个带有中间件的Route Group
中:
Route::group(['prefix' => '/admin/hotels', 'middleware' => ['permission:manage_hotels']], function () {
Route::get('/', 'HotelsController@index')->name('admin.hotels.index');
Route::post('/', 'HotelsController@create')->name('admin.hotels.create');
});
然后我将创建一个Permission
中间件:
class Permission
{
public function handle($request, Closure $next, $permission)
{
//if not super admin (super admin role_id is 1)
if(auth()->user()->role_id != 1) {
//explode extra param passed to this middleware (here manage_hotels)
$permission_array = explode('_', $permission);
foreach ($permission_array as $key => $value) {
$permission_array[$key] = ucfirst($value);
}
$permission_name = implode(' ', $permission_array);
$permitted = auth()->user()->role->permissions()->where('name', $permission_name)->first();
if(! $permitted) {
return redirect()->route('admin.dashboard')->withErrors(['error' => ['message' => 'You are not allowed to perform this action.']]);
}
}
return $next($request);
}
}
当然,您需要将这些路由包装到Admin Middleware
中,以确保用户已登录并具有管理员角色。