(MS ACCESS)SQL to groups join statement

时间:2016-07-14 09:40:05

标签: ms-access-2010 jet-sql

早上好!

我有一个MS Access拆分数据库(不使用ms sql server(还)),它们将几个表连接到临时查询(富有想象力地称为" temp"!)

SELECT table_CORE.[core-ID],
table_CORE.[PO],
table_CORE.[Part],
table_CORE.[Part Rev],
table_CORE.[Supplier Doc #],
table_CORE.[Sup Doc Rev],

table_DATES.[date-ID],
table_DATES.[iteration],

table_REJECTIONS.[rejection-ID],
table_REJECTIONS.[iteration],
table_REJECTIONS.[reason],
table_REJECTIONS.[details],
table_REJECTIONS.[timestamp]

FROM 
    (
        (
            table_CORE  INNER JOIN [TEMP] 
            ON table_CORE.[core-ID] = TEMP.[date-ID]
        )
        INNER JOIN [table_DATES] 
            ON TEMP.[date-ID] = table_DATES.[date-ID]
            AND TEMP.[iteration]=table_DATES.[iteration]
    ) 
    INNER JOIN table_REJECTIONS 
        ON TEMP.[date-ID] = table_REJECTIONS.[rejection-ID]
        AND TEMP.[iteration]=table_REJECTIONS.[iteration]
WHERE table_CORE.[core-ID] Like '*'

最终,这会显示一份文档拒绝列表 - 这很好,除了每个文档都适用于多个部分。

你可以将PO,Part和Part Rev捆绑在一起以将这些拒绝合并到一个文档中 - 问题是我通常会使用GROUP BY克劳斯做到这一点......

...除了"详细信息" field是一个memo数据类型,当您尝试GROUP BY子句时,access会将其截断为256个字符。

任何想法如何解决这个问题?我在加入rejeciton表之前尝试了组子句,但我最终遇到了同样的问题(因为有多个拒绝,同一个PO,部件号和修订版绑在一起) - 而且我'调查其他方法,但我无法理解它所需的SQL!

非常感谢!

如果您需要更多详情,请给我一个大喊!

---其他细节---

示例:

ID      PO      Part    Rev reason  details
1       111     A1      A   error   some_details1   
2       111     A1      A   error   some_details1
3       111     A1      A   error   some_details1
4       222     A1      A   error   some_details1
6       222     A1      A   error   some_details1
7       333     B1      A   error   some_details1
8       333     B1      A   error   some_details1
9       444     B1      A   error   some_details1
10      555     C1      A   error   some_details1

需要更改为:

PO      Part    Rev reason  details
111     A1      A   error   some_details1   
222     A1      A   error   some_details1
333     B1      A   error   some_details1
444     B1      A   error   some_details1
555     C1      A   error   some_details1

关于连接功能如何工作的注意事项:

当前项目存储在CORE中,并通过 core-ID>> date-ID 绑定到具有一对多关系的日期,然后使用迭代来获取最新内容部分历史中的事件。

然后使用core- ID>> rejeciton-ID AND date-iteration>> rejectioniteration 将最近的事件连接到拒绝列表以返回目前主动拒绝。

1 个答案:

答案 0 :(得分:0)

事实证明我可以欺骗并让MS为我编写SQL!

遵循AllenBrowne在查询编辑器中的建议(而不是使用SQL Directly),并使用FIRST()而不是GROUP BY()聚合table_REJECTIONS.details已修复它!

尽管如此令人讨厌的是 - 查询的原始SQL如下所示。

SELECT table_CORE.PO, 
table_CORE.Part, 
table_CORE.[Part Rev], 
table_CORE.[Supplier Doc #], 
table_CORE.[Sup Doc Rev], 
table_REJECTIONS.reason, 
First(table_REJECTIONS.details) AS details

FROM 
    (
        (
        table_CORE INNER JOIN TEMP
        ON  table_CORE.[core-ID] = TEMP.[date-ID]
        )
        INNER JOIN table_DATES 
        ON 
            (
                TEMP.[iteration] = table_DATES.[iteration]
            ) 
        AND 
            (
                TEMP.[date-ID] = table_DATES.[date-ID]
            )
    )
        INNER JOIN table_REJECTIONS 
        ON 
        (
            TEMP.[iteration] = table_REJECTIONS.[iteration]
        ) 
    AND 
        (
            TEMP.[date-ID] = table_REJECTIONS.[rejection-ID]
        )

WHERE table_CORE.[core-ID] Like '*' 
GROUP BY table_CORE.PO, 
table_CORE.Part, 
table_CORE.[Part Rev], 
table_CORE.[Supplier Doc #], 
table_CORE.[Sup Doc Rev], 
table_REJECTIONS.reason;