PHP - 通过根据值

时间:2016-07-14 08:38:17

标签: php arrays

我有多维数组,看起来像这样。这是我在下面的片段:

$tyreSpec = array(
    'width_id' => array(
        0 => '8',
        1 => '24'
    ),
    'profile_id' => array(
        0 => '8',
        1 => '13'
    ),
    'diameter_id' => array(
        0 => '4',
        1 => '13'
    ),
    'speed_id' => array(
        0 => '6',
        1 => '13'
    ),
    'load_id' => array(
        0 => '12',
        1 => '31'
    )
);

如何从上面创建这样的数组?

$toDb = array (
    array(
          'width_id' => 8,
          'profile_id' => 8,
          'diameter_id' => 4,           
          'speed_id' => 6,
          'load_id' => 12
    ),
    array(
          'width_id' => 24,
          'profile_id' => 13,
          'diameter_id' => 13,           
          'speed_id' => 13,
          'load_id' => 31
    )
);

这是我的代码,我无法完成它:

$ToDb = array();
//$i = 0;
$count = 0;
foreach($tyreSpec as $row ) {
    $count = count($row);
}

for($i = 0; $i < $count; $i++) {
    foreach($tyreSpec as $row) {
        array_push($ToDb, $row[$i]);
    }
}

3 个答案:

答案 0 :(得分:4)

您可以使用两个简单的循环来实现目标:

$toDb = array();
foreach ($tyreSpec as $key=>$val) {
    for ($i=0; $i<count($val); ++$i)
        $toDb[$i][$key] = $val[$i];
}

答案 1 :(得分:0)

我认为你正在寻找这个:

// $source is your input array
$result = [];$result = [];
array_walk($source, function($v,$k) use (&$result){
    $result[0][$k] = $v[0];
    $result[1][$k] = $v[1];
});

print_r($result);

演示是Here

答案 2 :(得分:0)

{{1}}