Question

错误：

c = dbConnection.execute（＆＃34; SELECT compid FROM＆＃34; + tableToUse +＆＃34; WHERE id =？＆＃34;，id） sqlite3.ProgrammingError：提供的绑定数量不正确。当前语句使用1，并且提供了2个。

当我这样做时：

def getcompid (dbConnection, tableToUse, id):
    c = dbConnection.execute("SELECT compid FROM " + tableToUse + " WHERE id = ?", id)

manualcompid = [('8','from01'),('35','28')]
for manid in manualcompid:

    ERROR:
    foundid = getcompid (dbConnection, tableToUse, manid[0])

    OR SAME ERROR:

    r = str(manid[0])
    foundid = getcompid (dbConnection, tableToUse, r)


    THE BELOW IS FINE:
    foundid = getcompid (dbConnection, tableToUse, '8')

它对我的接触r应该是简单的＆＃39; string与＆＃39; 8＆＃39;相同，更多manid[0]已经是字符串。为什么错误？

为什么我必须使用：foundid = getcompid (dbConnection, tableToUse, (manid[0],))？

Answer 1

绑定需要在列表或元组中。试试这个：

c = dbConnection.execute(
    "SELECT compid FROM " + tableToUse + " WHERE id = ?", [id])

Python 3.5 sqlite3传递字符串参数 - 提供的绑定数量不正确

1 个答案: