我试图在Windows 10应用程序(使用MVVM)中实现一个Flyout菜单,该菜单在按住GridView的项目时打开。我一直在寻找,但我找不到任何适合我的例子。弹出菜单未打开以显示选项。有谁知道我该怎么做?
<GridView.ItemTemplate>
<DataTemplate>
<StackPanel Orientation="Horizontal">
<FlyoutBase.AttachedFlyout>
<MenuFlyout>
<MenuFlyoutItem Text="Delete" Command="{Binding DeleteCommand}"/>
</MenuFlyout>
</FlyoutBase.AttachedFlyout>
<Image Source="{Binding Dictionary}" Height="25"/>
<TextBlock Text="{Binding Title}" Foreground="White" Width="170"/>
</StackPanel>
</DataTemplate>
</GridView.ItemTemplate>
中找到解决方案
答案 0 :(得分:1)
我认为你想要设置的是StackPanel.Flyout而不是FlyoutBase
<GridView.ItemTemplate>
<DataTemplate>
<StackPanel Orientation="Horizontal">
<StackPanel.Flyout>
<MenuFlyout>
<MenuFlyoutItem Text="Delete" Command="{Binding DeleteCommand}"/>
</MenuFlyout>
</StackPanel.Flyout>
<Image Source="{Binding Dictionary}" Height="25"/>
<TextBlock Text="{Binding Title}" Foreground="White" Width="170"/>
</StackPanel>
</DataTemplate>
</GridView.ItemTemplate>
或者如果这对您不起作用,您可以定位GridViewItem.Flyout
<GridView>
<GridView.Resources>
<Style TargetType="GridViewItem">
<Setter Property="Flyout">
<Setter.Value>
<MenuFlyout>
<MenuFlyoutItem Text="Delete" Command="{Binding DeleteCommand}"/>
</MenuFlyout>
</Setter.Value>
</Setter>
</Style>
</Gridview.Resources>