在文件中查找X出现的字符串并替换为静态字符串

Question

我需要你再帮忙。我需要找到3和4次出现的逗号（在整行中）并用特定的字符串替换，让我们假设：

"Text","Text2","Text3","Text4","Text5"
"Text6","Text7","Text8","Text9","Text10"

现在，我想将Text4，Text9，Text5，Text10替换为eg。 “静态”

 "Text","Text2","Text3","Static","Static"
 "Text6","Text7","Text8","Static","Static"

我应该使用哪种功能？知道可能'sed'是适当的，但如何计算逗号？

编辑:(简单版本只有3个逗号）

我需要找到只有3次出现的逗号（在整行中）并用特定字符串替换，我们假设：

"Text","Text2","Text3","Text4","Text5"
"Text6","Text7","Text8","Text9","Text10"

现在，我想将Text4，Text9替换为eg。 “静态”

 "Text","Text2","Text3","Static","Text5"
 "Text6","Text7","Text8","Static","Text5"

Answer 1

这个awk单行程适用于给定的示例。它会更改第4和第5列/字段中的文本：

awk -F, -v OFS="," '{i=4;while(i<6)gsub(/\w+/,"Static",$(i++))}7' file