你好我有一个字符串列表
"REF Product: [Title: gr8vh1, id: 1]"
"REF Product: [Title: gr8vh1, id: 2434]"
"REF Product: [Title: gr8vh1, id: 324]"
如何从每个字符串中获取id,以便输出如下?
"REF Product: [Title: gr8vh1, id: 1]"
=> 1
"REF Product: [Title: gr8vh1, id: 2434]"
=> 2434
"REF Product: [Title: gr8vh1, id: 324]"
=> 324
答案 0 :(得分:0)
尝试类似
的内容"REF Product: [Title: gr8vh1, id: 1]".scan(/id: (\d+)/).flatten[0].to_i
=> 1
答案 1 :(得分:0)
如果Title永远不会以整数开头,我会看到一个更简单的模式:
str = "REF Product: [Title: gr8vh1, id: 2434]"
str[/ \d+/].strip #regex to find integer after whitespace
#=> "2434"
答案 2 :(得分:0)
您可以从此字符串创建Hash
:
h = Hash[s[/\[(.*)\]/, 1].split(", ").map(&:split)]
# => {"Title:"=>"gr8vh1", "id:"=>"1"}
puts h["id:"]
# => "1"