SAXParseException,但XML非常好

时间:2016-07-06 21:05:43

标签: java xml jaxb saxparseexception

我有这个服务器必须从客户端接收xml文件。一切正常,我的服务器创建一个新的xml文件。之后我尝试使用JAXB从XML文件中读取,但是我得到了SAXParseException。我已尝试使用多个文件,而在另一个类中它可以正常工作,但不在Server类

 private void saveFile(Socket clientSock) throws IOException, JAXBException {
    DataInputStream dis = new DataInputStream(clientSock.getInputStream());
    FileOutputStream fos = new FileOutputStream("testfile.xml");
    byte[] buffer = new byte[4096];

    int filesize = 15123; // Send file size in separate msg
    int read = 0;
    int totalRead = 0;
    int remaining = filesize;
    while((read = dis.read(buffer, 0, Math.min(buffer.length, remaining))) > 0) {
        totalRead += read;
        remaining -= read;
        System.out.println("read " + totalRead + " bytes.");
        fos.write(buffer, 0, read);
    }
    fos.close();
    dis.close();
    JAXBContext jac;

        jac = JAXBContext.newInstance(Product.class,Order.class,Orders.class,Products.class);
        Marshaller jaxbMarshaller = jac.createMarshaller();
        jaxbMarshaller.setProperty( Marshaller.JAXB_FORMATTED_OUTPUT, true );


        Unmarshaller jaxbUnmarshaller = jac.createUnmarshaller();
        **Orders newOrders = (Orders)jaxbUnmarshaller.unmarshal( new File("testfile.xml"));**
        System.out.println( newOrders.getOrders().get(1).getId() );

0 个答案:

没有答案