Question

我有两张表backup_policy和backup_settings。 backup_policy有一个名为backup_settings_id的外键字段，其中backup_settings id字段已映射。这是为了创建两个表之间的关系而执行的查询

ALTER TABLE `backup_policy_scheduler`
ADD FOREIGN KEY (`backup_policy_id`) REFERENCES `backup_policy` (`id`)

现在的问题是，当我尝试这段代码时，屏幕会继续加载并给我最大的执行错误。

$repository=$this->getDoctrine()>getRepository('AppBundle:BackupPolicy');
$settings = $repository->findAll();

当我准备一个sql语句并执行fetchAll（）时，它会获取结果。

当我尝试插入记录时，它会给我以下错误：

类型错误：传递给AppBundle \ Entity \ BackupPolicy :: setBackupSettings（）的参数1必须是AppBundle \ Entity \ BackupSettings的实例，给定字符串，在/ var / www / symfonyproject / src / AppBundle / Controller / BackupPolicyController中调用第46行的.php

<?php

 namespace AppBundle\Entity;

 use Doctrine\ORM\Mapping as ORM;

 /**
* BackupPolicy
*
* @ORM\Table(name="backup_policy")
  *@ORM\Entity(repositoryClass="AppBundle\Entity\Repository\BackupPolicyRepository")
*/
class BackupPolicy
{
/**
 * @var integer
 *
 * @ORM\Column(name="id", type="integer", nullable=false)
 * @ORM\Id
 * @ORM\GeneratedValue(strategy="IDENTITY")
 */
private $id;

/**
 * @var \BackupSettings
 *
 * @ORM\ManyToOne(targetEntity="BackupSettings")
 * @ORM\JoinColumns({
 *   @ORM\JoinColumn(name="backup_settings_id", referencedColumnName="id")
 * })
 */
private $backupSettings;


/**
 * Get id
 *
 * @return integer
 */
public function getId()
{
    return $this->id;
}

/**
 * Set backupSettings
 *
 * @param \AppBundle\Entity\BackupSettings $backupSettings
 *
 * @return BackupPolicy
 */
public function setBackupSettings(\AppBundle\Entity\BackupSettings $backupSettings = null)
{
    $this->backupSettings = $backupSettings;

    return $this;
}

/**
 * Get backupSettings
 *
 * @return \AppBundle\Entity\BackupSettings
 */
public function getBackupSettings()
{
    return $this->backupSettings;
}
}

Answer 1

您只能插入BackupSettings实体。

在您的控制器行46中。

不是：

$backupPolicy->setBackupSettings('setting1');

但是像：

$repo=$this->getDoctrine()>getRepository('AppBundle:BackupSetting');
$backupPolicy->setBackupSettings($repo->findOneBy(array('name'=>'setting1'));

Symfony3外键关系实体不起作用

1 个答案: