Question

如何匹配网址/[a-z0-9]/phpmyadmin/？如果url匹配regex = /^\/([a-z0-9])+\/phpmyadmin/g 如何将组捕获到char以进行进一步操作？

例如，我有这个

char *url = "/zs0099/phpmyadmin";

我希望将其与正则表达式/^\/([a-z0-9])+\/phpmyadmin/g匹配如果匹配则

char *token = "zs0099"; //(how to get this value to assigned here)

Answer 1

从臀部快速射击（但没有pcre），裸C（小状态机）

#include <stdio.h>
#include <string.h>
#include <ctype.h>

int isMatch( char *url, char *p ) {
    int state= 0;
    while ( *url != 0 ) {
        switch (state) {
            // first state: char must be '/'
            case 0: 
               if (*url != '/') return 0;
               state=1;
               url++;
               break;
            // only characters and numbers are valid, another '/' ends this
            case 1: 
               if (isalpha(*url) || isdigit(*url)) { *p++=*url; url++; break; }
               if (*url == '/') { url++; state=2; break; }
               return 0; // not alhanum nor '/' --> not valid;
               break;
           case 2:
               *p++=0;
               if (strcmp(url, "phpmyadmin")==0) return 1;
               return 0;
           }
   }
   return 0;
}

int main() {
    char part[256];

    char *x1 = "/019sasA/phpmyadmin";
    int matches = isMatch(x1, part);
    printf ("%s, %i --> %s \n", x1, matches , matches ? part : "");

    char *x2 = "/019sasA/phpadmin";
    matches = isMatch(x2, part);
    printf ("%s, %i --> %s \n", x2, matches , matches ? part : "");

    char *x3 = "/019sa,sA/phpmyadmin";
    matches = isMatch(x3, part);
    printf ("%s, %i --> %s \n", x3, matches , matches ? part : "");
}

可能的问题：
“// phpmyadmin”有效（可以轻松修复另一个状态，第一个状态只接受isdigit（）和isnumber（），no'/'） “/ phpmyadmin”无效

如何使用pcre库来匹配c程序中的url

1 个答案: