我有两个清单：
lst1 = [{u'Hours': [{u'HourOfDay': 15, u'TotalVisits': 1, u'TotalTimeSpent': 7223.0},
{u'HourOfDay': 12, u'TotalVisits': 3, u'TotalTimeSpent': 37550.0}],
u'DayOfWeek': 1},
{u'Hours': [{u'HourOfDay': 19, u'TotalVisits': 6, u'TotalTimeSpent': 23497.0}],
u'DayOfWeek': 2},
{u'Hours': [{u'HourOfDay': 12, u'TotalVisits': 10, u'TotalTimeSpent': 36453.0}],
u'DayOfWeek': 3},
{u'Hours': [{u'HourOfDay': 13, u'TotalVisits': 22, u'TotalTimeSpent': 0.0},
{u'HourOfDay': 13, u'TotalVisits': 3, u'TotalTimeSpent': 4800.0}],
u'DayOfWeek': 4},
{u'Hours': [{u'HourOfDay': 9, u'TotalVisits': 5, u'TotalTimeSpent': 11879.0},
{u'HourOfDay': 8, u'TotalVisits': 1, u'TotalTimeSpent': 924.0},
{u'HourOfDay': 19, u'TotalVisits': 1, u'TotalTimeSpent': 8075.0}],
u'DayOfWeek': 5},
{u'Hours': [{u'HourOfDay': 19, u'TotalVisits': 1, u'TotalTimeSpent': 426.0},
{u'HourOfDay': 14, u'TotalVisits': 1, u'TotalTimeSpent': 1528.0}],
u'DayOfWeek': 6},
{u'Hours': [{u'HourOfDay': 17, u'TotalVisits': 8, u'TotalTimeSpent': 0.0}],
u'DayOfWeek': 7}]
lst2 = [{u'Hours': [{u'HourOfDay': 3, u'TotalVisits': 2, u'TotalTimeSpent': 127.0},
{u'HourOfDay': 12, u'TotalVisits': 2, u'TotalTimeSpent': 107.0}],
u'DayOfWeek': 1},
{u'Hours': [{u'HourOfDay': 8, u'TotalVisits': 1, u'TotalTimeSpent': 3.0},
{u'HourOfDay': 7, u'TotalVisits': 1, u'TotalTimeSpent': 14.0}],
u'DayOfWeek': 2},
{u'Hours': [{u'HourOfDay': 8, u'TotalVisits': 1, u'TotalTimeSpent': 85.0},
{u'HourOfDay': 0, u'TotalVisits': 10, u'TotalTimeSpent': 1634.0}],
u'DayOfWeek': 3},
{u'Hours': [{u'HourOfDay': 8, u'TotalVisits': 10, u'TotalTimeSpent': 719.0},
{u'HourOfDay': 17, u'TotalVisits': 1, u'TotalTimeSpent': 2.0}],
u'DayOfWeek': 4},
{u'Hours': [{u'HourOfDay': 23, u'TotalVisits': 2, u'TotalTimeSpent': 32.0},
{u'HourOfDay': 20, u'TotalVisits': 3, u'TotalTimeSpent': 322.0},
{u'HourOfDay': 21, u'TotalVisits': 1, u'TotalTimeSpent': 0.0}],
u'DayOfWeek': 5},
{u'Hours': [{u'HourOfDay': 8, u'TotalVisits': 1, u'TotalTimeSpent': 548.0},
{u'HourOfDay': 17, u'TotalVisits': 2, u'TotalTimeSpent': 40.0}],
u'DayOfWeek': 6},
{u'Hours': [{u'HourOfDay': 3, u'TotalVisits': 3, u'TotalTimeSpent': 5324.0},
{u'HourOfDay': 20, u'TotalVisits': 2, u'TotalTimeSpent': 45.0}],
u'DayOfWeek': 7}]
它们由DayOfWeek分隔，而小时列表包含dicts，每个dicts在一天中的不同时段具有不同的数据。两个列表都用于单独的数据。我想在这两个列表中添加花费的总时间和访问次数，并从中创建一个新的类似列表。即如果同一DayOfWeek的HourOfDay相同，则添加TotalTimeSpent和总访问次数，否则将信息附加到Hours列表。我不想错过任何数据，只需附加两个，因为他们可能没有一天中的几个小时的数据，但我仍然希望它们在最后一个。
我想要的是每天两个列表的并集，如果同一DayOfWeek的两个集合的HourOfDay字段相同，则添加TotalVisits和TotalTimeSpent。
我试过了：
final = lst1[::]
i = j = 0
for item1, item2 in zip(lst1,lst2):
for hr1 in item1["Hours"]:
for hr2 in item2["Hours"]:
if hr1["HourOfDay"] == hr2["HourOfDay"]:
print "i: {0} ;; j: {1}".format(i,j)
final[i]["Hours"][j]["TotalTimeSpent"] = hr1["TotalTimeSpent"] + hr2["TotalTimeSpent"]
j += 1
i += 1
j = 0
print final
但它将它们加起来并在lst2中每个dict的Hours列表中遗漏了值，因为显而易见的原因，这些值在lst1中不存在。请帮忙！
答案 0 :(得分：1)
好的，这是一个使用您当前数据结构的解决方案，我个人觉得这很愚蠢，因为它将列表中最糟糕的方面与字典中最糟糕的方面结合起来：
final = []
for d1,d2 in zip(list1,list2):
new = {'DayOfWeek':d1['DayOfWeek'], 'Hours':[]}
d1copy = d1['Hours'][:]
d2copy = d2['Hours'][:]
for hr1 in d1['Hours']:
for hr2 in d2['Hours']:
if hr1["HourOfDay"] == hr2["HourOfDay"]:
ttspent = hr1["TotalTimeSpent"] + hr2["TotalTimeSpent"]
tvisits = hr1['TotalVisits'] + hr2['TotalVisits']
combo = {'HourOfDay':hr1['HourOfDay'],
'TotalTimeSpent':ttspent,
'TotalVisits':tvisits}
new['Hours'].append(combo)
d1copy.remove(hr1)
d2copy.remove(hr2)
new['Hours'].extend(d1copy)
new['Hours'].extend(d2copy)
final.append(new)
结果：
[{'DayOfWeek': 1,
'Hours': [{'HourOfDay': 12, 'TotalTimeSpent': 37657.0, 'TotalVisits': 5},
{'HourOfDay': 15, 'TotalTimeSpent': 7223.0, 'TotalVisits': 1},
{'HourOfDay': 3, 'TotalTimeSpent': 127.0, 'TotalVisits': 2}]},
{'DayOfWeek': 2,
'Hours': [{'HourOfDay': 19, 'TotalTimeSpent': 23497.0, 'TotalVisits': 6},
{'HourOfDay': 8, 'TotalTimeSpent': 3.0, 'TotalVisits': 1},
{'HourOfDay': 7, 'TotalTimeSpent': 14.0, 'TotalVisits': 1}]},
{'DayOfWeek': 3,
'Hours': [{'HourOfDay': 12, 'TotalTimeSpent': 36453.0, 'TotalVisits': 10},
{'HourOfDay': 8, 'TotalTimeSpent': 85.0, 'TotalVisits': 1},
{'HourOfDay': 0, 'TotalTimeSpent': 1634.0, 'TotalVisits': 10}]},
{'DayOfWeek': 4,
'Hours': [{'HourOfDay': 13, 'TotalTimeSpent': 0.0, 'TotalVisits': 22},
{'HourOfDay': 13, 'TotalTimeSpent': 4800.0, 'TotalVisits': 3},
{'HourOfDay': 8, 'TotalTimeSpent': 719.0, 'TotalVisits': 10},
{'HourOfDay': 17, 'TotalTimeSpent': 2.0, 'TotalVisits': 1}]},
{'DayOfWeek': 5,
'Hours': [{'HourOfDay': 9, 'TotalTimeSpent': 11879.0, 'TotalVisits': 5},
{'HourOfDay': 8, 'TotalTimeSpent': 924.0, 'TotalVisits': 1},
{'HourOfDay': 19, 'TotalTimeSpent': 8075.0, 'TotalVisits': 1},
{'HourOfDay': 23, 'TotalTimeSpent': 32.0, 'TotalVisits': 2},
{'HourOfDay': 20, 'TotalTimeSpent': 322.0, 'TotalVisits': 3},
{'HourOfDay': 21, 'TotalTimeSpent': 0.0, 'TotalVisits': 1}]},
{'DayOfWeek': 6,
'Hours': [{'HourOfDay': 19, 'TotalTimeSpent': 426.0, 'TotalVisits': 1},
{'HourOfDay': 14, 'TotalTimeSpent': 1528.0, 'TotalVisits': 1},
{'HourOfDay': 8, 'TotalTimeSpent': 548.0, 'TotalVisits': 1},
{'HourOfDay': 17, 'TotalTimeSpent': 40.0, 'TotalVisits': 2}]},
{'DayOfWeek': 7,
'Hours': [{'HourOfDay': 17, 'TotalTimeSpent': 0.0, 'TotalVisits': 8},
{'HourOfDay': 3, 'TotalTimeSpent': 5324.0, 'TotalVisits': 3},
{'HourOfDay': 20, 'TotalTimeSpent': 45.0, 'TotalVisits': 2}]}]
答案 1 :(得分：0)
这是一个非常奇怪的字典结构，你甚至在一周中的几天都使用非零数字刻度。我花了一些时间来解析你的数据结构，但是这里发生了什么：＆/ p>
lst1和lst2被构造为对象列表，如下所示：[{object Day 1}，{object Day 2}，... {object Day 7}]
这些列表中的每个对象都可以进一步分解为具有两个键的对象 - ＆＃34;小时＆＃34;和＆＃34; DayOfWeek＆＃34;：
object for Day x = {
Hours: [list of other objects with keys for HourOfDay, TotalVisits, and TotalTimeSpent],
DayOfWeek: x }
尽管如此，使用dicts列表并不具有内存效率，因此我建议使用多维列表进行快速检索和更新。
# Create a new list of lists that will be accessible by [day][hour]
# This 7 x 24 array will contain dicts containing data for TotalVisits and TotalTimeSpent.
# This will permit O(1) retrieval for relevant entries by day & hour
# I've included _Day and _Hour in the dict for the sake of readability
# (if you have more time, you can even make these immutable with a Base class)
newObject = [[{'_Day':i,'_Hour':j,'TotalVisits':0,'TotalTimeSpent':0} \
for j in range(0,24)] for i in range(1,8)]
# Iterate over items in lst1, lst2 and add data to our new object
# Don't forget to adjust the index for your days so that you don't get
# an index-out-of-bounds error.
# (Yet another reason why you should number your days 0-6 instead of 1-7.)
combinedList = lst1 + lst2
for item in combinedList:
day = item['DayOfWeek'] # This will return an int 1-7; needs to be adjusted to zero-scale
visitEntries = item['Hours'] # This will return a list of dicts
for i in visitEntries:
hour = i['HourOfDay']
# Add visit data to our new object for each day, hour
newObject[day-1][hour]['TotalVisits'] += i['TotalVisits']
newObject[day-1][hour]['TotalTimeSpent'] += i['TotalTimeSpent']
# To see results:
for i in range(0,7):
for j in range(0,24):
print newObject[day][hour]