我有一个父div,它连续有几个子div。子div的总宽度大于父div和我的屏幕的宽度。我希望文本“CENTERED X CENTERED”能够水平居中。我不希望显示滚动条。我必须使用white-space:nowrap。
<div style="width:100%; overflow:hidden; text-align:center">
<div style="display:inline-block; white-space:nowrap; width:100%; margin-left:auto; margin-right:auto; text-align:center">
<div style="display:inline-block">My text... My text... My text... My text... My text... My text... My text... My text... My text... My text... My text... My text... My text... My text... My text... My text... My text...</div>
<div style="display:inline-block">CENTERED X CENTERED</div>
<div style="display:inline-block">My text... My text... My text... My text... My text... My text... My text... My text... My text... My text... My text... My text... My text... My text... My text... My text... My text...</div>
</div>
我如何修改我的代码?
答案 0 :(得分:0)
你能使用额外的div吗?最外层是溢出:隐藏,所以使额外的div超宽 - 比内容更宽。然后,您可以使用一些聪明的CSS来集中它:
https://jsfiddle.net/5cvujqd3/
git master
<div class="outer">
<div class="inner">
<!-- inline-block stuff here -->
</div>
</div>
答案 1 :(得分:0)
使用#include <iostream>
#include <stack>
using namespace std;
void main()
{
stack<int> myStack;
int userFactor, tempFactor, stackLoop;
int runTotal = 0;
cout << "Enter number to be factorialized: ";
cin >> userFactor;
tempFactor = userFactor;
if (userFactor == 1 || userFactor == 0) //a "base case" of sorts
cout << endl << userFactor << " factorialized is 1.\n";
else
{
while (tempFactor > 1) //load the stack
{
myStack.push(tempFactor);
tempFactor--;
}
runTotal = myStack.top(); //start unloading the stack
myStack.pop();
stackLoop = (int)myStack.size();
for (int x = 0; x < stackLoop; x++) //multiply each
{
runTotal *= myStack.top();
myStack.pop();
}
cout << endl << userFactor << " factorialized is: " << runTotal << endl;
}
}
,transform:translateX()
和white-space:nowrap
overflow:hidden;
.parent {
overflow: hidden;
}
.parent > div {
display: inline-block;
white-space: nowrap;
position: relative;
left: 50%;
transform: translateX(-50%);
}
.parent > div > div {
display: inline-block;
}