Question

我做了'猜数字'游戏，但我想添加输入验证，这样用户只能猜测一个整数。这是我的代码，我感谢任何建议。我正在使用python 3。

import random
print('Hello, what is your name?')
name = input()
print('It is nice to meet you ' + name + '.')
secretNumber = random.randint(1, 20)
print('Well ' + name + ', I am thinking of a number between 1 and 20')
for guessTaken in range(1, 7):
    print('Take a guess.')
    guess = int(input())
    if guess < secretNumber:
        print('Your guess is too low.')
    elif guess > secretNumber:
        print('Your guess is too high.')
    else:
        break
if guess == secretNumber:
    print('Good job ' + name + '. You guessed my number in %d guesses' %(guessTaken))
else:
    print('Nope. My number was ' + str(secretNumber) + '.')

Answer 1

def input_int(prompt=">",error_msg="That is not an int!"):
    while True:
         try:
             return int(input(prompt))
         except ValueError:
              print(error_msg)

x = input_int("Please Enter an Int:","Wrong Answer!")
print x,x**2

你可以进一步抽象

def input_type(typeClass=str,prompt="?",error_msg="Wrong Padawan"):
     while True:
          try:
             return typeClass(input(prompt))
          except ValueError:
             print(error_msg)

input_type(int,"Enter an int:","Thats not an int!")
input_type(float,"Enter a float:","Thats not a float!")
input_type(FunkyChickenClass,"Enter a name for your chicken:","Thats wrong!")

或

def  input_int(prompt="Enter Int:",error_msg="Not an int!"):
     return input_type(int,prompt,error_msg)

Answer 2

这是使用输入验证执行此操作的更好方法

import random
name = raw_input('Hello, what is your name?')
print('It is nice to meet you ' + name + '.')
secretNumber = random.randint(1, 20)
print('Well ' + name + ', I am thinking of a number between 1 and 20')
for guessTaken in range(1, 7):
    guess = 0
    invalid = True
    while invalid:
        try:
            guess = int(raw_input('Take a guess'))
            invalid = False
        except ValueError:
            print 'You must enter an integer'
    if guess < secretNumber:
        print('Your guess is too low.')
    elif guess > secretNumber:
        print('Your guess is too high.')
    else:
        break
if guess == secretNumber:
    print('Good job ' + name + '. You guessed my number in %d guesses' %(guessTaken))
else:
    print('Nope. My number was ' + str(secretNumber) + '.')

Answer 3

for guessTaken in range(1, 7):
    guess = 0
    while guess < 1 or guess > 20:
        print('Take a guess.')
        try:
           guess = int(input())
        except ValueError:
           print("Guess must be a number.")
        else:
           if guess < 1 or guess > 20:
               print("Guess must be between 1 and 20.")
           else:
               print("Your guess is:", guess)
    if guess < secretNumber:
        # continue your code

在'for'循环中尝试除外 - Python

3 个答案: