Question

我有一个大约1000个单个整数的列表。我需要能够进行一些数学计算，但它们会被列入列表或字符形式。如何切换它们才能使用？

示例数据：

> y [[1]] 
  [1] "7" "3" "1" "6" "7" "1" "7" "6" "5" "3" "1" "3" "3" "0" "6" "2" "4" "9" 
  [19] "1" "9" "2" "2" "5" "1" "1" "9" "6" "7" "4" "4" "2" "6" "5" "7" "4" "7"     
  [37] "4" "2" "3" "5" "5" "3" "4" "9" "1" "9" "4" "9" "3" "4" "9" "6" "9" "8" 
  [55] "3" "5" "2" "0" "3" "1" "2" "7" "7" "4" "5" "0" "6" "3" "2" "6" "2" "3" 
  [73] "9" "5" "7" "8" "3" "1" "8" "0" "1" "6" "9" "8" "4" "8" "0" "1" "8" "6" ...

只是前几行。

Answer 1

参见？unlist：

> x
[[1]]
[1] "1"

[[2]]
[1] "2"

[[3]]
[1] "3"


> y <- as.numeric(unlist(x))

> y
[1] 1 2 3

如果这不能解决您的问题，请说明您想要做什么。

编辑：它显然更简单：

> x <- list(as.character(1:3))

> x
[[1]]
[1] "1" "2" "3"


> y <-as.numeric(x[[1]])

> y
[1] 1 2 3

Answer 2

试试这个 - 结合as.numeric()和rbind()：

> foo <- list("2", "4", "7")
> foo
[[1]]
[1] "2"

[[2]]
[1] "4"

[[3]]
[1] "7"

> bar <- do.call(rbind, lapply(foo, as.numeric))
> bar
     [,1]
[1,]    2
[2,]    4
[3,]    7
>

在R中列出整数或双精度

2 个答案: