SQLite查询WHERE子句的麻烦

Question

您好我是Android的初学者，在我的应用程序中，我使用SQLite存储下面的详细信息

1. 名称
2. PRODUCTCODE
3. mobileNo
4. 电子邮件

这里我的问题是WHERE子句我的意思是我想使用name和productCode来过滤记录，为此我写了下面的代码，但我得到例外，请帮助我一些

MainActivity：

public Cursor searchDetails(String user_name,String productName, SQLiteDatabase db) {
    Cursor cursor = db.rawQuery("select * from " + UserContactDetails.NewUSerInfo.TABLE_NAME + " where" +UserContactDetails.NewUSerInfo.USER_NAME= '" +user_name + "' and UserContactDetails.NewUSerInfo.PRODUCT_CODE ='"+productName+ "'", null);
    return cursor;
}

userDbHelper：

com.example.ram_ramadevi.sqllitetutorial, PID: 31620    
android.database.sqlite.SQLiteException: near "fromuser_infowhere": syntax error (code 1): , while compiling: select * fromuser_infowhere type = ramand name =8008824731

logcat的： 过程：

soup=BeautifulSoup(html, "lxml", from_encoding='utf-8')

Answer 1

我认为在连接查询字符串时错过了那里的空格

 public Cursor searchDetails(String user_name,String productName, SQLiteDatabase db) {

        Cursor cursor = db.rawQuery("select * from " + UserContactDetails.NewUSerInfo.TABLE_NAME + " where type = '" +user_name + "' and name = '"+productName+"'", null);
        return cursor;
    } 

Answer 2

试试这个......

public Cursor searchDetails(String user_name,String productName, SQLiteDatabase db) {

Cursor cursor = db.rawQuery("select * from " + UserContactDetails.NewUSerInfo.TABLE_NAME + " where type = '" +user_name + "' and name ='"+productName+ "'", null);
     return cursor;
  }