我的问题是有没有办法使用Reflection?
检索参数列表及其值我想使用反射从PropertyInfo中获取参数列表。
Author author = (Author)attribute;
string name = author.name;
不行。因为会有很多属性,这不是作者的类型。
[AttributeUsage(AttributeTargets.Class | AttributeTargets.Property, AllowMultiple = true)]
public class Author : Attribute
{
public Author(string name, int v)
{
this.name = name;
version = v;
}
public double version;
public string name;
}
public class TestClass
{
[Author("Bill Gates", 2)]
public TextBox TestPropertyTextBox { get; set; }
}
答案 0 :(得分:4)
使用此程序
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace ConsoleApplication1 {
class Program {
static void Main(string[] args) {
Console.WriteLine("Reflecting TestClass");
foreach (var property in typeof(TestClass).GetProperties()) {
foreach (Author author in property.GetCustomAttributes(typeof(Author), true).Cast<Author>()) {
Console.WriteLine("\tProperty {0} Has Author Attribute Version:{1}", property.Name, author.version);
}
}
var temp = new TestClass();
Console.WriteLine("Reflecting instance of Test class ");
foreach (var property in temp.GetType().GetProperties()) {
foreach (Author author in property.GetCustomAttributes(typeof(Author), true).Cast<Author>()) {
Console.WriteLine("\tProperty {0} Has Author Attribute Version:{1}", property.Name, author.version);
}
}
}
}
[AttributeUsage(AttributeTargets.Class | AttributeTargets.Property, AllowMultiple = true)]
public class Author : Attribute {
public Author(string name, int v) {
this.name = name;
version = v;
}
public double version;
string name;
}
public class TestClass {
[Author("Bill Gates", 2)]
public TextBox TestPropertyTextBox { get; set; }
}
}
我得到了这个输出:
答案 1 :(得分:0)
我假设参数列表是指所有属性用途的列表?
如果没有,此代码将向您展示如何使用整个类的反射来获取属性。但是你应该能够得到你需要的东西。
所以这是一种在TestClass
public IEnumberable<Result> GetAttributesFromClass(TestClass t)
{
foreach(var property in t.GetType().GetProperties())
{
foreach(Author author in property.GetCustomAttributes(typeof(Arthor), true))
{
// now you have an author, do what you please
var version = author.version;
var authorName = author.name;
// You also have the property name
var name = property.Name;
// So with this information you can make a custom class Result,
// which could contain any information from author,
// or even the attribute itself
yield return new Result(name,....);
}
}
}
然后你可以去:
var testClass = new TestClass();
var results = GetAttributesFromClass(testClass);
此外,您可能希望public double version
和string name
成为属性。
像这样:
public double version
{
get;
private set;
}
允许从构造函数设置version
,并从任何地方读取。
答案 2 :(得分:0)
string name = author.name;
是不允许的,因为字段name
不公开。如果你公开name
,它会起作用吗?
答案 3 :(得分:0)
我在其中一个应用中遇到了同样的问题。这是我的解决方案:
public static string GetAttributesData(MemberInfo member)
{
StringBuilder sb = new StringBuilder();
// retrives details from all attributes of member
var attr = member.GetCustomAttributesData();
foreach (var a in attr)
{
sb.AppendFormat("Attribute Name : {0}", a)
.AppendLine();
sb.AppendFormat("Constructor arguments : {0}", string.Join(", ", a.ConstructorArguments))
.AppendLine();
if (a.NamedArguments != null && a.NamedArguments.Count > 0 )
sb.AppendFormat("Named arguments : {0}", string.Join(", ", a.NamedArguments))
.AppendLine();
sb.AppendLine();
}
return sb.ToString();
}
我测试了你的例子。
var t = typeof (TestClass);
var prop = t.GetProperty("TestPropertyTextBox", BindingFlags.Public | BindingFlags.Instance);
var scan = Generator.GetAttributesData(prop);
这里是输出:
Attribute Name : [Author("Bill Gates", (Int32)2)]
Constructor arguments : "Bill Gates", (Int32)2