Question

我有一台服务器，里面有几张1.5 kb到9 Mb的照片。来自PC，平板电脑和手机的照片。服务器将它们编码为Base64字符串，然后将它们发送到Android客户端。在BitmapFactory.decodeByteArray中解码时，一个300 kb的照片返回null ...但是它是有效的图像并且在在线解码器中解码良好。

byte[] decodedString = Base64.decode(image64, Base64.DEFAULT);
Bitmap decodedByte = BitmapFactory.decodeByteArray(decodedString, 0, ecodedString.length);

2天我找不到答案（

有什么想法吗？谢谢！

P.S。

 private boolean decodeImage64(String uid, String image64, String name) {
    Bitmap decodedByte;
    boolean result = false;
    if (image64 != null && !image64.isEmpty()) {

        try {
            Log.e(TAG, "decodeImage64: image64.getBytes().length = " + image64.getBytes().length);
            byte[] decodedString = Base64.decode(image64, Base64.DEFAULT);
            Log.e(TAG, "decodeImage64: decodedString = " + decodedString + "  , decodedString.length = " + decodedString.length);
            decodedByte = BitmapFactory.decodeByteArray(decodedString, 0, decodedString.length);
            Log.e(TAG, "decodeImage64: decodedByte = " + decodedByte);

            if (decodedByte != null) {
                FileOutputStream out = null;
                try {
                    out = new FileOutputStream(getImageFolderName() + "/" + uid + ".png");
                    decodedByte.compress(Bitmap.CompressFormat.PNG, 100, out);
                    decodedByte.recycle();
                    out.close();

                } catch (Exception e) {
                    Log.e(TAG, Log.getStackTraceString(e));
                } finally {
                    try {
                        if (out != null) {
                            out.close();
                        }
                        if (decodedByte != null){
                            decodedByte.recycle();
                        }
                    } catch (IOException e) {
                        Log.e(TAG, Log.getStackTraceString(e));
                    }
                }
                result = true;
            }else {
                Log.e(TAG, "  !!!!!!!!!!!!!!!!!!!!!!! decodeImage64: decodedByte = null "  + name);
            }
        }catch (Exception e){
            Log.e(TAG, Log.getStackTraceString(e));
        }
    } else {
        Log.e(TAG, "decodeImage64: image = null " + name);
    }
    return result;
}

和logcat

好的形象：

06-29 02:33:57.465 18197-18584/cps.agrovisio E/myLogs:  ------------------------- doInBackground: Good photo
06-29 02:34:13.993 18197-18584/cps.agrovisio E/myLogs: decodeImage64: image64.getBytes().length = 2264744
06-29 02:34:14.085 18197-18584/cps.agrovisio E/myLogs: decodeImage64: decodedString = [B@bb8956d  , decodedString.length = 1676499
06-29 02:34:14.635 18197-18584/cps.agrovisio E/myLogs: decodeImage64: decodedByte = android.graphics.Bitmap@a6d05a2

糟糕的形象：

06-29 02:33:56.041 18197-18584/сps.agrovisio E/myLogs:  ------------------------- doInBackground: Bad photo 
06-29 02:33:57.177 18197-18584/cps.agrovisio E/myLogs: decodeImage64: image64.getBytes().length = 372570
06-29 02:33:57.194 18197-18584/cps.agrovisio E/myLogs: decodeImage64: decodedString = [B@abcf243  , decodedString.length = 275799
06-29 02:33:57.245 18197-18584/cps.agrovisio E/myLogs: decodeImage64: decodedByte = null

Answer 1

这可能不是您正在寻找的答案，但您是否考虑过使用框架？我一直在使用毕加索，它很简单： Picasso.with（上下文）.load（＆＃34; http://i.imgur.com/DvpvklR.png＆＃34）。到（ImageView的）;

http://square.github.io/picasso/

Answer 2

从data:image/jpg;base64,切割部分image64。只有编码的字符串。

你可以使用substring方法，它可以工作。

Android BitmapFactory在Base64解码字节数组上返回null

2 个答案: