Question

我是SQL Server的新手并且正在努力解决这个问题。

我有两个选择语句

SELECT 
    SUM(Amount) AS "MONDAY" 
FROM 
    Transaction 
WHERE 
    Transaction_Date = '2015-12-21 00:00:00.000'

SELECT 
    SUM(Amount) AS "TUESDAY" 
FROM 
    Transaction 
WHERE 
    Transaction_Date = '2015-12-22 00:00:00.000'

他们的结果分别为2,00,000和3,00,000

我希望输出显示为两列

SQL Server屏幕上的

（第1列+星期一）和（第2列=星期二）

Answer 1

一种选择是使用conditional aggregation：

SELECT SUM(CASE WHEN Transaction_Date = '2015-12-21 00:00:00.000'  
           THEN Amount END) AS "MONDAY" ,
       SUM(CASE WHEN Transaction_Date = '2015-12-22 00:00:00.000' 
           THEN Amount END) AS "TUESDAY" 
FROM Transaction

Answer 2

select datepart(dw, transactiondate),
    sum(amount) [sum]
from transaction
where transaction_date between '2015-12-22' and '2015-12-23'
group by datepart(dayofweek, transactiondate)

请记住，这是伪代码，我正在查找“dayofweek”属性......

查找日期部分：https://msdn.microsoft.com/en-us/library/ms174420.aspx

Answer 3

我认为您需要使用MSSQL Pivot函数将行转换为列。检查另一个问题。也许这可以帮助你： Convert Rows to columns using 'Pivot' in SQL Server

SQL Sum Query问题

3 个答案: