Question

我尝试过使用ROW_NUMBER，但还没有得到它。关于实现这一目标的最佳方法的任何想法。

我希望找到：

- What month did they first cash flow.

- What month did they average 3 months cash flow.

示例数据：办公室，平衡＆amp;年月

  ------------------------------
  |  Office | Balance |  YrMo  |
  |   12    |  111    | 201510 |
  |   12    |  222    | 201511 |
  |   12    | -444    | 201512 |
  |   12    | -777    | 201601 |
  |   12    |  555    | 201602 |
  |   12    |  666    | 201603 |
  |   12    | -888    | 201604 |
  |   12    |  777    | 201605 |
  |   40    | -555    | 201510 |
  |   40    | -200    | 201511 |
  |   40    |  0      | 201512 |
  |   40    |  100    | 201601 |
  |   40    | -555    | 201602 |
  |   40    |  666    | 201603 |
  |   40    |  777    | 201604 |
  |   40    |  888    | 201605 |
  |   40    |  999    | 201606 |

第一个正余额将是：

-office 12 , Balance 111 , YrMo 201510
-office 40 , Balance 100 , YrMo 201601

办公室第一个月平均3个正余额：

-office 40 , Balance 999 , YrMo 201606

这是#test表脚本：

IF OBJECT_ID('tempdb..#test') IS NOT NULL
DROP TABLE #test
GO

CREATE TABLE #test (office INT , Balance INT, YrMo INT ) ;

INSERT  INTO #test VALUES  (12 ,  111 , 201510) ;
INSERT  INTO #test VALUES  (12 ,  222 , 201511) ;
INSERT  INTO #test VALUES  (12 , -444 , 201512) ;
INSERT  INTO #test VALUES  (12 , -777 , 201601) ;
INSERT  INTO #test VALUES  (12 ,  555 , 201602) ;
INSERT  INTO #test VALUES  (12 ,  666 , 201603) ;
INSERT  INTO #test VALUES  (12 , -888 , 201604) ;
INSERT  INTO #test VALUES  (12 ,  777 , 201605) ;
INSERT  INTO #test VALUES  (40 , -555 , 201510) ;
INSERT  INTO #test VALUES  (40 , -200 , 201511) ;
INSERT  INTO #test VALUES  (40 ,  0   , 201512) ;
INSERT  INTO #test VALUES  (40 , 100  , 201601) ;
INSERT  INTO #test VALUES  (40 , -555 , 201602) ;
INSERT  INTO #test VALUES  (40 , 666  , 201603) ;
INSERT  INTO #test VALUES  (40,  777  , 201604) ;
INSERT  INTO #test VALUES  (40 , 888  , 201605) ;
INSERT  INTO #test VALUES  (40 , 999  , 201606) ;

提前致谢

Answer 1

;with cteFirst as (
    Select *
          ,FirstPos=Row_Number() over (Partition By Office Order By YrMo,Balance) from #Test  Where Balance>0 
),
  cteCons as (
    Select * 
          ,TestCons=Lag(IIf(IIf(sign(balance)=1,1,0)=1,1,0),1,0) over (Partition By Office Order By YrMo)
                   +Lag(IIf(IIf(sign(balance)=1,1,0)=1,1,0),2,0) over (Partition By Office Order By YrMo)
                   +Lag(IIf(IIf(sign(balance)=1,1,0)=1,1,0),3,0) over (Partition By Office Order By YrMo)
    from #Test 
)
Select *,Status='First Positive' from cteFirst where FirstPos=1
Union All
Select *,Status='3 Cons' from cteCons where TestCons=3

返回

office  Balance YrMo    FirstPos    Status
12      111     201510  1           First Positive
40      100     201601  1           First Positive
40      999     201606  3           3 Consequtive

Answer 2

我又添了一个例子。这个陷阱在日期中存在差距。

如果要查看所有标志以及数据如何进展，请删除 - 之前选择*来自cteFinal Order by Office，YrMo

我添加了另一个办公室，其中有3个连续的正余额，但月份不是（没有6月）。通知Office 99无法满足连续月份标准

office  Balance YrMo
99      199     201605
99      299     201607
99      399     201608

更新的查询如下

;with cteBase as (
    Select *
          ,RowNr  = Row_Number() over (Partition By Office Order By Office,YrMo,Balance) 
          ,MthSeq = case when cast(YrMo as int)-Lag(YrMo,1,YrMo-1) over (Partition By Office Order By YrMo) in (1,89) then 1 else 0 end
          ,IsPos  = IIf(Balance>0,1,null)
     from #Test
)
,cteFinal as (
    Select *
          ,PosRowNr = min(RowNr*IsPos) over (Partition By Office Order By RowNr) 
          ,TestCons = MthSeq * (
                      Lag(IIf(IIf(sign(balance)=1,1,0)=1,1,0),1,0) over (Partition By Office Order By YrMo)
                     +Lag(IIf(IIf(sign(balance)=1,1,0)=1,1,0),2,0) over (Partition By Office Order By YrMo)
                     +Lag(IIf(IIf(sign(balance)=1,1,0)=1,1,0),3,0) over (Partition By Office Order By YrMo)
                     )
    From  cteBase
)
--Select * from cteFinal Order by Office,YrMo
Select Office
      ,Balance
      ,YrMo
      ,Status = IIf(RowNr=PosRowNr,'First Positive','')+IIf(TestCons=3,'Consecutive Months','')
 From cteFinal 
 Where TestCons=3 or RowNr=PosRowNr
 Order by Status Desc,Office,YrMo

结果

Office  Balance YrMo    Status
12      111     201510  First Positive
40      100     201601  First Positive
99      199     201605  First Positive
40      999     201606  Consecutive Months

如何在SQL中找到第一个正值和第三个连续正值？

2 个答案: