根据服务电话的响应,我有以下代码显示/隐藏成功div,我需要将服务响应的请求传递给成功Div
。如何通过requestId
并显示成功div
?
<div id="showResponseArea" class="alert alert-success hide">
<span>
<strong>Success !! </strong>Your request <<requestId>> has been successfuly created !!!
</span>
</div>
$.ajax({
url:
type:
data:
success: function(resObj){
$("#showResponseArea span").removeClass("hide");
var requestId = resObj.requestId;
}
error: funciton(resObj){
alert("Some Error Occured");
}
});
答案 0 :(得分:0)
首先,您要从错误的标记hide
中删除span
类,该标记没有该类。应该从父div中删除hide class,其中id =&#34; showResponseArea&#34;其中有hide类,其次你需要用{id}包裹<<requestId>>
。像
<div id="showResponseArea" class="alert hide">
<span>
<strong>Success !! </strong>Your request <span id="requestId"> // Request id goes here</span> has been successfuly created !!!
</span>
然后在ajax成功函数
success: function(resObj){
$("#showResponseArea").removeClass("hide");
$("#showResponseArea").removeClass("alert-danger");
$("#showResponseArea").addClass("alert-success");
//OR $("#showResponseArea").removeClass("hide").show();
var requestId = resObj.requestId;
$("#requestId").text(requestId );
},
error: function(err,xhr,status){
$("#showResponseArea").removeClass("hide");
$("#showResponseArea").removeClass("alert-success");
$("#showResponseArea").addClass("alert-danger");
//OR $("#showResponseArea").removeClass("hide").show();
$("#requestId").text(xhr.responseText);
}
答案 1 :(得分:0)
当您收到回复消息时,您可以在html中使用它。您可以根据需要修改响应消息,因此请在您的javascript代码中使用.html()来操作您的响应消息。例如,您的回复可以是“&lt; strong&gt;成功,很棒,foo foo foo!&lt; strong&gt;”或“&lt; strong&gt;错误,foo foo foo!&lt; strong&gt;”。使用ajax请求作为显示响应的函数,在您的req页面中生成响应消息。
HTML:
<div id="showResponseArea" class="alert alert-success"> <span></span> </div>
JS:
$.ajax({
url:
type:
data:
success: function(msg){
$("#showResponseArea span").html(msg); //you will paste your response msg to the span
}
error: funciton(msg){
alert("Some Error Occured");
}
});