我有xml
<CommonTestData>
<GiftCards>
<GiftCard>
<cardnumber>7777016774730834</cardnumber>
<number>1815</number>
</GiftCard>
<GiftCard>
<cardnumber>7777016774687937</cardnumber>
<number>6256</number>
</GiftCard>
</GiftCards>
我必须迭代这些xml并读取值并输入Selenium
Web应用程序并检查礼品卡应用量是否大于零。 If the amount applied is zero then try another card . If the amount applied is greater than zero then break the loop
我的代码看起来像
for (int i=0;i<xmlvalue.getNodeCount("GiftCard", "CommonTestData.xml");i++){
//giftcardaccordian.click();
giftcardnumber.sendKeys(xmlvalue.getValue("cardnumber"+i, "GiftCard", "CommonTestData.xml")); // I need code for getvalue function so that i can iterate through
giftcardpin.sendKeys(xmlvalue.getValue("cardnumber"+i, "GiftCard", "CommonTestData.xml"));
giftcardapplybutton.click();
try{
if(appliedgiftcardamount.getText()!="$0"){
break;
}
}catch (Exception e ){
Assert.fail("Cannot apply reward certicate");
}
}
我需要实现Getvalue,以便我可以迭代。现在我的实现类似于
public String getValue(String csstagname, String Elementname, String xmlfilename) {
String eElement1;
try {
String path = "config/XML/" + xmlfilename;
File fXmlFile = new File(path);
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
doc.getDocumentElement().normalize();
NodeList nList = doc.getElementsByTagName(Elementname);
for (int temp = 0; temp < nList.getLength(); temp++) {
Node nNode = nList.item(temp);
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
eElement1 = csstagname;
Element eElement2 = (Element) nNode;
value = (getTagValue(eElement1, eElement2));
}
}
} catch (Exception e) {
e.printStackTrace();
} finally {
return (value);
}
}
答案 0 :(得分:0)
您正在做的事情是可能的,但它不符合XML的精神。你控制XML文件吗?更改格式,以便卡号和号码有自己的总体标记将它们绑定在一起:
<CommonTestData>
<GiftCards>
<GiftCard>
<cardnumber>7777016774730834</cardnumber>
<number>1815</number>
</GiftCard>
<GiftCard>
<cardnumber>7777016774687937</cardnumber>
<number>6256</number>
</GiftCard>
</GiftCards>
</CommonTestData>
如果您不控制格式,请提取标有cardnumber
的所有节点,所有标记为number
的节点,然后访问具有相同索引的两个阵列。