我正在使用以下查询从子集中为每个ID1-ID2对随机抽取一行,这些记录具有最短的时间距离(YEAR和MMDD字段)。
CREATE TABLE temp4 AS
SELECT *
FROM temp3
GROUP BY ID1, ID2
ORDER BY DATEDIFF( CONCAT(YEAR,'-',LEFT(MMDD,2),'-',RIGHT(MMDD,2)), CONCAT(ID3_YEAR,'-',LEFT(ID3_MMDD,2),'-',RIGHT(ID3_MMDD,2)) ) ASC, RAND()
LIMIT 0, 1;
从我之前发布的上一个问题来看,这就是表格的样子
ID1 ID2 YEAR MMDD ID3 YEAR_ID3 MMDD_ID3
---------------------------------------
1 2 1991 0821 55 1991 0822
1 2 1991 0821 57 1991 0822
1 2 1991 0821 88 1992 0101
1 3 1990 0131 89 2000 0202
1 3 1990 0131 89 2001 0102
对于每个ID1-ID2对,我需要用
选择ID3时间上的最小距离(YEAR字段和MMDD字段,即我需要比较YEAR和MMDD与YEAR_ID3和MMDD_ID3)
如果超过一个ID3满足上面的最低要求(即它们都具有相同的YEAR_ID3和MMDD_ID3),我需要随机选择一个。
在上面的例子中,QUERY应该返回
1,2,1991,0821,55 (OR 1,2,1991,0821,57 - ACCORDING TO THE RANDOM DRAW)
1,3,1990,0131,89
我上面贴的一个只返回一行...... :(
在OMG发表的评论部分下面有一个很好的解决方案......但是它消失了?!?!?
我在这里粘贴
DROP TABLE IF EXISTS temp4;
CREATE TABLE temp4 AS
SELECT x.id1,
x.id2,
x.YEAR,
x.MMDD,
x.id3,
x.id3_YEAR,
x.id3_MMDD
FROM (SELECT t.*,
ABS(DATEDIFF(CONCAT(CAST(t.id3_YEAR AS CHAR(4)),'-', LEFT(t.id3_MMDD,2),'-',RIGHT(t.id3_MMDD,2)),
CONCAT(CAST(t.YEAR AS CHAR(4)),'-', LEFT(t.MMDD,2),'-',RIGHT(t.MMDD,2)))) AS diff,
CASE
WHEN @id1 = t.id1 AND @id2 = t.id2 THEN @rownum := @rownum + 1
ELSE @rownum := 1
END AS rk,
@id1 := t.id1,
@id2 := t.id2
FROM temp3 t
JOIN (SELECT @rownum := 0, @id1 := 0, @id2 := 0) r
ORDER BY t.id1, t.id2, diff, RAND()) x
WHERE x.rk = 1;
我在这里粘贴一个测试表的SQL转储
DROP TABLE IF EXISTS `temp3`;
CREATE TABLE IF NOT EXISTS `temp3` (
`id1` char(7) NOT NULL,
`id2` char(7) NOT NULL,
`YEAR` year(4) NOT NULL,
`MMDD` char(4) NOT NULL,
`id3` char(7) NOT NULL,
`id3_YEAR` year(4) NOT NULL,
`id3_MMDD` char(4) NOT NULL
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
INSERT INTO `temp3` VALUES('1', '2', 1992, '0107', '55', 1991, '0528');
INSERT INTO `temp3` VALUES('1', '2', 1992, '0107', '57', 1991, '0701');
INSERT INTO `temp3` VALUES('1', '3', 1992, '0107', '88', 2000, '0101');
INSERT INTO `temp3` VALUES('1', '3', 1992, '0107', '44', 2000, '0101');
答案 0 :(得分:0)
从查询中提取随机记录的常用方法是
SELECT [] FROM表ORDER BY RAND()LIMIT []