想要针对特定​​列值输出列值

Question

我想在给定的luggage_id中输出bid_amount列值。 以下是截图。 参考截图，例如如果luggage_id是123561，我想只获得bid_amounts 255,25和88。

我的控制器

public function bid(){

                            $this->load->database();  
                            $this->load->model('Truckeraccount_model');
                            $data['h']=$this->Truckeraccount_model->loads();  
                            redirect('truckeraccount_ctrl/');

}  

我的模特

public function loads()  {  

                            $luggage_id = $this->session->userdata('luggage_id'); 
                            $this->db->select('*');
                            $this->db->from('bids');
                            $this->db->where('luggage_id', $luggage_id); 
                            $query = $this->db->get('bids');
                            return $query; 
} 

我的观点

<?php

               foreach ($h->result() as $row)  
 {
?>   
Luggage: <?php echo $row->luggage_id;?><br>
Bids: $<?php echo $row->bid_amount;?>

<?php } ?>

数据被输出为单独的行。

Answer 1

这样做

在控制器中

public function bid(){

    $this->load->database();  
    $this->load->model('Truckeraccount_model');
    $data['bids']=$this->Truckeraccount_model->loads();  

    # remove below and load view
    //redirect('truckeraccount_ctrl/');

    $this->load->view('name', $data);

}  

在模型中

public function loads()  {  

    $luggage_id = $this->session->userdata('luggage_id'); 
    $this->db->select('*');
    $this->db->from('bids');
    $this->db->where('luggage_id', $luggage_id); 
    $query = $this->db->get('bids');
    $result = $query->result_array();
    return $result; 
} 

在视图中

foreach ($bids as $bid) {
    echo "Luggage ".$bid['luggage_id'];
    echo "Bids ".$bid['bid_amount']; ;
}