我正在创建一个"动画字母增量器"它接受任何给定的单词并从A开始递增该单词的每个字母。
示例:
Word = Dog
D - Increments from A to D [A, B, C, D]
O - Increments from A to O [A, B, C, D, E, F, G, H, I, J, K, L, M, N, O]
G - Increments from A to G [A, B, C, D, E, F, G]
我想要实现的效果类似于此jQuery animated number counter,除了我将增加字母而不是计算数字。此外,单词的每个字母应该独立增加,但它们应该同时到达目的地字母。
JS:
var wordToIncrement = 'DOG';
var alphabet = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ '.split('');
for (var i = 0, len = wordToIncrement.length; i < len; i++) {
var letterToIncrementTo = wordToIncrement[i];
var arrayLength = alphabet.length;
for (var z = 0; z < arrayLength; z++) {
var alphabetLetter = alphabet[z];
if (alphabetLetter == letterToIncrementTo) {
console.log('MATCH FOUND!');
console.log('Word Letter: ' + letterToIncrementTo);
console.log('Alphabet Letter: ' + alphabetLetter);
alphabetPositionValue = z;
console.log('VALUE: ' + alphabetPositionValue);
function incrementToLetter(letterToIncrementTo,alphabetPositionValue) {
// This is where I'm stuck
var div = document.getElementById('#word_block');
div.innerHTML = div.innerHTML + 'Extra stuff';
}
}
}
}
HTML:
<div id="work_block"></div>
如何完成上面的代码以实现与动画数字计数器示例类似的功能并增加单词的每个字母?我正在寻找基于javascript的解决方案。
答案 0 :(得分:1)
我会建立一个保持字母和时间的字母对象。这样,您可以在对象上提供简单的更新功能,对象本身将确保它生成正确的当前字母。
function Letter(table, letter, duration) {
this.table = table; // lookup-table
this.letter = letter; // target letter
this.current = 0; // index in table
this.delay = duration / tbl.indexOf(letter); // ms
this.time = Date.now(); // current (start) time
this.done = false; // status
}
然后是一个常见的原型update()
方法:
Letter.prototype.update = function() {
if (this.done) return; // if done, do no more
var time = Date.now(); // get current time
if (time - this.time >= this.delay) { // exceeded delay?
this.time = time; // store current time
if (this.letter === this.table[this.current] ||
this.current === this.table.length) { // target reached? unknown letter
this.done = true; // we're done
}
else {
this.current++; // next in table
}
}
};
然后我们可以从字符串中生成对象:
var letters = [];
word.toUpperCase().split("").forEach(function(l) {
letters.push(new Letter(tbl, l, 2500)); // 2.5s duration
});
然后给它制作动画:
(function loop() {
var txt = "", isDone = true;
letters.forEach(function(l) {
l.update();
if (!l.done) isDone = false;
txt += l.table[l.current];
});
// output txt
if (!isDone) requestAnimationFrame(loop);
else { /* done */ }
})();
function Letter(table, letter, duration) {
this.table = table;
this.letter = letter;
this.current = 0;
this.delay = duration / tbl.indexOf(letter); // ms
this.time = Date.now();
this.done = false;
}
Letter.prototype.update = function() {
if (this.done) return;
var time = Date.now();
if (time - this.time >= this.delay) {
this.time = time;
if (this.letter === this.table[this.current] ||
this.current === this.table.length) {
this.done = true;
}
else {
this.current++;
}
}
};
var word = "hello there";
var tbl = " ABCDEFGHIJKLMNOPQRSTUVWXYZ";
var letters = [];
word.toUpperCase().split("").forEach(function(l) {
letters.push(new Letter(tbl, l, 2500))
});
(function loop() {
var txt = "", isDone = true;
letters.forEach(function(l) {
l.update();
if (!l.done) isDone = false;
txt += l.table[l.current];
});
// output txt
d.innerHTML = txt;
if (!isDone) requestAnimationFrame(loop);
else { /* done */ }
})();
#d {font:bold 32px monospace}
<div id=d></div>
如果延迟低于16.7ms,则可能无法足够快地增加。它可以通过将当前相对时间除以持续时间来解决。将此标准化值乘以表中目标字母的索引以获取当前值,将结果四舍五入为整数值。
您可以提供不同的表格来获取随机性/变异。