Question

所以，我知道这是如此基本，但我收到此错误：我该怎么做才能修复它？ y.y

Traceback（最近一次调用最后一次）：文件＆＃34; / home / coding / Documents / Python Repository / 2 - Numbers＆amp;数学（贷款 Calclator）.py＆＃34;，第40行，in monthly_payment = float（loan_amount）* [0.05 *（1.0 + 0.05）* float（num_of_payments）] / [（1.0 + 0.05）* float（num_of_payments） - 1.0] TypeError：不能将序列乘以非int类型＆＃39; float＆＃39;

#Loan Calculator

#Monthly Payments formula > M = L[i(1+i)n] / [(1+i)n-1]
# M = Month Payment
# L = Loan amount
# i = interest rate (int rate of 5%, i = 0.05)
# n = number of payments


print ('Hey there! Welcome to Johnny\'s Loan Bank!')

#just set variable
monthly_payment = 0

#Set how much money user will need
loan_input = input('So, how much would you like to lend? ')

#transform the input in a float
loan_amount = float(loan_input)


#Set number of months to pay
num_of_pay_input = input('And in how many months would you like to pay? ')

#transform value into a float
num_of_payments = float(num_of_pay_input)

print ('\nSo, you want to lend {0:.1f} in {1:.1f} payments'.format(loan_amount, num_of_payments))
print ('You should know that we work with an interest rate of 5%')

#Variable set to know the users decision
user_decision = input('Would you like to continue?: ')
print (user_decision)

if user_decision == 'y' or decision == 'yes':
    print ('loan_amount {0:.1f}'.format(loan_amount))
    print ('num_of_payments {0:.1f}'.format(num_of_payments))

Line 40>>>>     monthly_payment = float(loan_amount) * [0.05 * (1.0 + 0.05) * float(num_of_payments)] / [(1.0 + 0.05) * float(num_of_payments) - 1.0]

    print ('Ok, you\'ll get a loan of {0:.1f} and you gonna pay us in {1:.1f} months'.format(loan_amount, num_of_payments) + \
        ', thats gonna be {0:.1f} for month.'.format(monthly_payment))
else:
    print ('get off my bank')

Answer 1

在你的行中：

    monthly_payment = float(loan_amount) * [0.05 * (1.0 + 0.05) * float(num_of_payments)] / [(1.0 + 0.05) * float(num_of_payments) - 1.0]

您使用方括号（在本例中用于创建列表）作为指定操作顺序的方法。这应该是()类型括号。

Python - 我的代码出了什么问题？

1 个答案: