Question

无法通过像其他人那样接受服务器套接字来解决此问题。（永远锁定;见下面的评论]

   import java.net.*;
import java.io.*;

public class one_hundred
{
   public static void main(String [] args)
   {
       String hostName = "pool-72-83-252-59.washdc.fios.verizon.net";
       int portNumber = 3281;
      try
      {
         /*
         Open a socket.
Open an input stream and output stream to the socket.
Read from and write to the stream according to the server's protocol.
Close the streams.
Close the socket.
*/
         Socket server = new Socket(hostName, portNumber);

         OutputStream outToServer = server.getOutputStream();
         DataOutputStream out = new DataOutputStream(outToServer);
          out.writeUTF("mJFr1vJBIcpYTtIui6yLrzQw " + server.getLocalSocketAddress());
         InputStream inFromServer = server.getInputStream();
         DataInputStream in = new DataInputStream(inFromServer);
         System.out.println(in.readUTF());
         server.close();
      }catch(IOException e)
      {
         e.printStackTrace();
      }
   }
}

如何在没有ss的情况下解决这个问题？（或者以某种方式解决套接字锁定问题？

另一种尝试也失败了：

   import java.io.*;
import java.net.*;
import java.net.Socket;
public class onehundred
{
    public static void main(String args[]) throws java.io.IOException
     {String urlParameters = "fName=" + URLEncoder.encode("???", "UTF-8") + "&lName=" + URLEncoder.encode("???", "UTF-8");
        request("http://codeabbey.sourceforge.net", urlParameters);}
public static String request(String gotourl, String urlParameters)
{    HttpURLConnection connection = null;  

     try 
   {     InetAddress locIP = InetAddress.getByName("0.0.0.0");
     ServerSocket serverSocket = new ServerSocket(8080, 0, locIP);
     //Create connection
    URL url = new URL(gotourl);
    connection = (HttpURLConnection)url.openConnection();
    connection.setRequestMethod("POST");
    connection.setRequestProperty("/say-100.php", "Token: 9PaF2QQmZBFX+K3+LlI5ozky");
    connection.setUseCaches(false);
    connection.setDoOutput(true);

    //Send request
    DataOutputStream wr = new DataOutputStream (connection.getOutputStream());
    wr.writeBytes(urlParameters);
    wr.close();

    //Get Response  
    InputStream is = connection.getInputStream();
    BufferedReader rd = new BufferedReader(new InputStreamReader(is));
    StringBuilder response = new StringBuilder();
    String line;
    while((line = rd.readLine()) != null) 
    { response.append(line);
      response.append('\r');
    }
    rd.close();
    System.out.println(response); //System.out.println(line); also prints out nothing
    return response.toString();
   } catch (Exception e) 
    {e.printStackTrace();
    return null;
    } finally 
      {
    if(connection != null) 
       {connection.disconnect();}
     }
   }
}

Answer 1

这两行毫无意义;

您实例化一个新的ServerSocket，但您使用Class来调用.accept（）;

ServerSocket ss = new ServerSocket();
ss = ServerSocket.accept();

改为写下：

ServerSocket ss = new ServerSocket();
Socket socket = ss.accept();

Answer 2

发布您的编辑：

ServerSocket和Socket在这里完全没有意义。你没有使用它们。您的代码将在accept()中阻止，可能会永久阻止。将它们都移除。

未知主机异常错误[非重复]

2 个答案: