我有一个ToggleButton设置如下:
final ToggleButton filterButton = (ToggleButton) findViewById(R.id.filterTags);
filterButton.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
if (filterButton.isChecked()) {
// pop up the list of tags so the user can choose which to filter by
// once one is chosen, the spinner will be updated appropriately
showDialog(DIALOG_TAGS);
} else {
// going unpressed, set the the spinner list to everything
updateSpinner(db.itemNames());
}
}
});
,对话框如下:
case DIALOG_TAGS:
final String[] tagNames = db.tagNamesInUse();
dialog = new AlertDialog.Builder(this)
.setItems(tagNames, new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
updateSpinner(db.getItemNamesForTag(tagNames[which]));
final ToggleButton filterButton = (ToggleButton) findViewById(R.id.filterTags);
filterButton.setTextOn(tagNames[which]);
dialog.dismiss();
}
})
.setNegativeButton("Cancel", UITools.getDialogCancellingListener())
.create();
这个想法是:如果打开ToggleButton,它会弹出一个单选列表视图对话框,它是标签列表。选择标记后,它将成为ToggleButton的新textOn。如果关闭ToggleButton(unChecked),则文本将恢复为静态TextOff。
问题是:一旦对话框消失,按钮就不会被重绘。显示的文本仍然是textOn的先前值。
如何强制重绘?我试过filterButton.postInvalidate();
,但没有帮助。
答案 0 :(得分:19)
解决!明智地读取ToggleButton的源代码表明,虽然setTextOn()和setTextOff()不会导致调用更新TextView位的(私有)syncTextState,但调用setChecked()会。所以诀窍是:
dialog = new AlertDialog.Builder(this)
.setItems(tagNames, new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
updateSpinner(db.getItemNamesForTag(tagNames[which]));
final ToggleButton filterButton = (ToggleButton) findViewById(R.id.filterTags);
filterButton.setTextOn(tagNames[which]);
filterButton.setChecked(filterButton.isChecked());
dialog.dismiss();
}
})
哪个效果很好。耶和开源!