Question

我想使用AWS lambda来制作cronjob风格的HTTP请求。不幸的是，我不了解Python。

我发现他们有一个＆＃34; Canary＆＃34;功能似乎与我想要的相似。如何简化此操作以简单地发出HTTP请求？我只需要触发一个PHP文件。

from __future__ import print_function

from datetime import datetime
from urllib2 import urlopen

SITE = 'https://www.amazon.com/'  # URL of the site to check
EXPECTED = 'Online Shopping'  # String expected to be on the page


def validate(res):
    '''Return False to trigger the canary

    Currently this simply checks whether the EXPECTED string is present.
    However, you could modify this to perform any number of arbitrary
    checks on the contents of SITE.
    '''
    return EXPECTED in res


def lambda_handler(event, context):
    print('Checking {} at {}...'.format(SITE, event['time']))
    try:
        if not validate(urlopen(SITE).read()):
            raise Exception('Validation failed')
    except:
        print('Check failed!')
        raise
    else:
        print('Check passed!')
        return event['time']
    finally:
        print('Check complete at {}'.format(str(datetime.now())))

Answer 1

您可以使用请求（http://docs.python-requests.org/en/master/）以更轻松的方式处理响应。

import requests

URL = 'https://www.amazon.com/'
def lambda_handler(event, context):
    requests.get(URL)

Answer 2

该程序将“简单地发出HTTP请求。”

from urllib2 import urlopen

SITE = 'https://www.amazon.com/'  # URL of the site to check

def lambda_handler(event, context):
    urlopen(SITE)

Lambda函数可以生成简单的HTTP请求

2 个答案: