Question

我有一个简单的案例类位置（这几乎是ScalaJsonCombinators教程）

<TypeOfId> id = hm.get(c.getPhone());
if(id != null) {
    registered_phone_contacts.add(new Contact(id, c.getName());

...                                           ^^
}

我想在构造上设置当前时间，以便我的位置看起来像：

// controller
implicit val locationWrites: Writes[Location] =
(
  (JsPath \ "latitude").write[Double] and
  (JsPath \ "longitude").write[Double]
) (unlift(Location.unapply))

implicit val locationReads: Reads[Location] =
(
  (JsPath \ "latitude").read[Double] and
  (JsPath \ "longitude").read[Double]
) (Location.apply _)

// model
case class Location(latitude: Double, longitude: Double)

object Location {
  implicit val formatter = Json.format[Location]
}

不幸的是，我无法弄清楚如何使用Play Json传递LocalDateTime.now（）而不发送额外的字段或实际上如何传递LocalDateTime。

请求正文

case class Location(latitude: Double, longitude: Double, date: LocalDateTime)

Answer 1

不是将Location.unapply / Location.apply传递给FunctionalBuilder，而是可以传递自己的功能：

case class Location(latitude: Double, longitude: Double, date: LocalDateTime)

implicit val locationWrites: Writes[Location] =
(
  (JsPath \ "latitude").write[Double] and
  (JsPath \ "longitude").write[Double]
) ((l: Location) => (l.latitude, l.longitude))

implicit val locationReads: Reads[Location] =
(
  (JsPath \ "latitude").read[Double] and
  (JsPath \ "longitude").read[Double]
) ((lat: Double, lon: Double) => Location(lat, lon, LocalDateTime.now()))

Scala Play在构造上读取Json和LocalDateTime

1 个答案: