我的问题是我在webview中创建的链接无法正常工作,然后当我点击它时,它不会转到另一个Activity,那么我的错误在哪里? 请帮忙!!!谢谢
prknln1.loadDataWithBaseURL("file:///android_asset",Perkenalan,"text/html","utf-8",null);
prknln1.setWebViewClient(new WebViewClient() {
public boolean shouldOverrideUrlLoading(WebView view, String url) {
Intent i;
{
if (url.equalsIgnoreCase("TabHiragana")) {
i = new Intent(getApplicationContext(), TabHiragana.class);
startActivity(i);
} else if (url.equalsIgnoreCase("TabKatakana")) {
i = new Intent(getApplicationContext(), TabKatakana.class);
startActivity(i);
} else if (url.equalsIgnoreCase("Kanji")) {
i = new Intent(getApplicationContext(), List_Kanji.class);
startActivity(i);
}
}
Log.e("URL", "URL" + url);
return true;
}
});
答案 0 :(得分:0)
我认为您将检查网址中的特定字词,因为您需要使用包含方法。
prknln1.loadDataWithBaseURL("file:///android_asset",Perkenalan,"text/html","utf-8",null);
prknln1.setWebViewClient(new WebViewClient() {
public boolean shouldOverrideUrlLoading(WebView view, String url) {
Intent i;
{
if (url.contains("TabHiragana")) {
i = new Intent(getApplicationContext(), TabHiragana.class);
startActivity(i);
} else if (url.contains("TabKatakana")) {
i = new Intent(getApplicationContext(), TabKatakana.class);
startActivity(i);
} else if (url.contains("Kanji")) {
i = new Intent(getApplicationContext(), List_Kanji.class);
startActivity(i);
}
}
Log.e("URL", "URL" + url);
return true;
}
});
答案 1 :(得分:0)
打开一个活动并将参数传递给它:
在您的文字数据(myText)中,有网址:
"<a href=\"" + word + "\">" + word + "</a>"
加载数据:
webView.loadDataWithBaseURL("file:///android_asset", myText, "text/html", "utf-8", null);
setWebViewClient:
webView.setWebViewClient(new WebViewClient() {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
if (url.startsWith("file")) {
Intent intent = new Intent(MyActivity.this, MyActivity.class);
intent.putExtra("word", Uri.parse(url).getLastPathSegment());
startActivity(intent);
return true;
} else
return false;
}
});